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pashok25 [27]
4 years ago
6

Question about Conduction!

Physics
2 answers:
vladimir1956 [14]4 years ago
4 0
He should buy the wooden spoon because the metal spoon would conduct heat and the plastic spoon would melt
spayn [35]4 years ago
4 0
He should buy the wooden spoon. The metal one would conduct heat and burn him. The plastic spoon could melt.
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If in the experiment, m1 is 38 g, m2 is 63 g, and m3 is 58 g, "and m3 remains static, what is the tension in the string connecti
melomori [17]
Let's call a the acceleration of the system. The problem says that the block m3 is static, so the acceleration is zero: a=0.
Calling T_1 the tension of the string between m1 and m3, and T_2 the tension of the string between m2 and m3, the problem can be solved by writing the following system of equations:
m_1 g-T_1=m1_a
T_1-T_2=m_3 a
T_2-m_2g=m_2a
However, we know that a=0 and the problem asks only for T_1, so we just need to solve the first equation:
m_1 g -T_1 =0
and so
T_1=m_1g=0.038~kg \cdot 9.81~m/s^2 = 0.37~N
7 0
3 years ago
Help please help help help
poizon [28]
Mass (m) of the object is 1kg
Velocity (v) is 2m/s
and the height is 0
when the mechanical energy M.E is solved for m*v= 1(2)=2 so the M.E=2
3 0
3 years ago
At the first Democratic Party convention of 1860, fifty Southern delegates refused to vote and left the convention. voted to sec
marysya [2.9K]

Answer:

A) refused to vote and left the convention.

Explanation:

At the first Democratic Party convention of 1860, fifty Southern delegates <u>refused to vote and left the convention </u>

3 0
3 years ago
Read 2 more answers
In Millikan's experiment, an oil drop of radius 1.362 μm and density 0.888 g/cm3 is suspended in chamber C when a downward-point
Misha Larkins [42]

Answer:

The charge on the oil drop is 3e

Explanation:

F = qE

Where;

F is the applied force in Newton

E is the electric field potential N/C

q is charge in C

Given;

Radius, r = 1.362 μm = 1.362 X 10⁻⁶ m

density, ρ = 0.888 g/cm³ = 0.888 X 10³ kg/m³

Electric field potential = 1.92 ✕ 10⁵ N/C

F =mg

mass of the oil drop = density, ρ  X volume of the oil drop

volume of the oil drop (spherical) =  (4/3)πr³ = 1.3333π(1.362 X 10⁻⁶)³

⇒ volume of the oil drop = 10.584 X 10⁻¹⁸ m³

mass of the oil drop = 0.888 X 10³ (kg/m³) X 10.584 X 10⁻¹⁸ (m³)

⇒ mass of the oil drop = 9.399 X 10⁻¹⁵ kg

⇒ F =mg = 9.399 X 10⁻¹⁵ kg X 9.8 = 9.21 X10⁻¹⁴ N

F = qE

q = F/E

q = (9.21 X10⁻¹⁴)/(1.92 ✕ 10⁵) = 4.797 X 10⁻¹⁹ C

In terms of e

1e = 1.6 X10⁻¹⁹ C

=  (4.797 X 10⁻¹⁹ C)/(1.6 X10⁻¹⁹ C) = 3e

Therefore, the charge on the oil drop is 3e

7 0
3 years ago
3. A car advertisement states that a certain car can accelerate from rest to 70 km/h in 7 seconds.
kozerog [31]

Answer:

10 km/s^2

Explanation:

Acceleration = velocity/time

a= 70km/7s

= 10km/s^2

8 0
3 years ago
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