Answer:
C. Count the atoms in each substance in the reactants and products.
Explanation:
A chemical reaction can be defined as a chemical process which typically involves the transformation or rearrangement of the atomic, ionic or molecular structure of an element through the breakdown and formation of chemical bonds to produce a new compound or substance.
In order for a chemical equation to be balanced, the condition which must be met is that the number of atoms in the reactants equals the number of atoms in the products.
This ultimately implies that, the mass and charge of the chemical equation are both balanced properly.
In Chemistry, all chemical equation must follow or be in accordance with the Law of Conservation of Mass, which states that mass can neither be created nor destroyed by either a physical transformation or a chemical reaction but transformed from one form to another in an isolated (closed) system.
One of the step used for balancing chemical equations is to count the atoms in each substance in the reactants and products.
For example;
NH3 + O2 -----> NO + H2O
The number of atoms in each chemical element are;
For the reactant side:
Nitrogen, N = 1
Hydrogen, H = 3
Oxygen, O = 2
For the product side;
Nitrogen, N = 1
Hydrogen, H = 2
Oxygen, O = 2
When we balance the chemical equation, we would have;
NH3 + 3O2 -----> 4NO + 2H2O
-- If the force is applied in the <em>same direction</em> as the object is moving, then the object's momentum in that direction will <em>increase</em>.
-- If the force is applied in the direction <em>OPPOSITE </em>to the way the object is moving, then the object's momentum will <em>decrease</em>.
-- In either case, the CHANGE in the object's momentum will be
(strength of the force) x (length of time the force is applied) .
This quantity is also called "impulse".
Answer:
A: Time is represented by dots at 1-second intervals.
D: Velocity vectors change direction as the object’s direction changes.
Explanation:
If he's traveling at 5.2 m/s, then he covers
5.2 meters in the 1st second
5.2 meters in the 2nd second
5.2 meters in the 3rd second
5.2 meters in the 4th second
.
.
.
.
5.2 meters in the 14th second, and
5.2 meters in the 15th second.
He covers 5.2 meters 15 times in 15 seconds.
To find the total distance, you could write down 5.2 meters
15 times and add them all up. Or you could use the newly-
discovered, labor-saving process called 'multiplication' to do
the same thing. With multiplication, it can be done in one line:
(5.2 m/s) x (15 sec) = 78 meters .
