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Xelga [282]
3 years ago
12

Which sets of data show a wave with the shortest wavelength? A. Speed=100 million m/s and frequency = 50 million Hz. B. Speed=15

0 million m/s and frequency=1500 Hz C.Speed=300 million m/s and frequency= 100 Hz
Physics
1 answer:
SashulF [63]3 years ago
3 0
The answer is <span>A. Speed=100 million m/s and frequency = 50 million Hz.</span>

Let's calculate for each choice the wavelength using the equation:
v = f × λ   ⇒ λ = v ÷ f<span>

where:
v - the speed,
f - the frequency,
</span>λ - the wavelength.

A:
v = 100 000 000 m/s
f = 50 000 000 Hz = 50 000 000 1/s (Since f = 1/T, so units are Hz = 1/s)
⇒ λ = 100 000 000 ÷ 50 000 000 = 2 m

B:
v = 150 000 000 m/s
f = 1 500 Hz = 1 500 1/s
⇒ λ = 150 000 000 m/s ÷ 1 500 = 100 000 m

B:
v = 300 000 000 m/s
f = 100 Hz = 100 1/s
⇒ λ = 300 000 000 m/s ÷ 100 = 3 000 000 m

According to these calculations, the shortest wavelength is needed for choice A.
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Answer:

p(t)=\frac{1}{20}(1+2e^{-t/90})

Explanation:

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(\% CO_2 \ in\  Fresh\  Air \times \frac{1}{100})\times(Rate \ of  Outflow\ of \ air)\\=(p\times\frac{1}{100})\times2=\frac{p}{50}

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180\frac{dp}{dt}=\frac{1}{10}-2p\\\frac{dp}{dt}=\frac{1-20p}{1800}\\\\\frac{dp}{20p-1}=-\frac{dt}{1800}

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\int\limits \frac{dp}{20p-1}=\int\limits-\frac{dt}{1800}

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+20In \ C=+In \ K

Raise both sides to base e,

20p-1=e^{-\frac{t}{90}+In \ K}\\\\p=\frac{1}{20}(1+Ke^{-t/90})

Initially, there's only 0.25% of CO_2,

Now substitute p=0.25 and t=0

0.25=\frac{1}{20}(1+K)\\K=4

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