Answer:
4.6 m
Explanation:
First of all, we can find the frequency of the wave in the string with the formula:
where we have
L = 2.00 m is the length of the string
T = 160.00 N is the tension
is the mass linear density
Solving the equation,
The frequency of the wave in the string is transmitted into the tube, which oscillates resonating at same frequency.
The n=1 mode (fundamental frequency) of an open-open tube is given by
where
v = 343 m/s is the speed of sound
Using f = 37.3 Hz and re-arranging the equation, we find L, the length of the tube:
Answer:
a,b,c,d,,f, g, j
Explanation:
e) equipotential lines are lines connecting points of equal potential
h) electric field inside the conductor is non-zero even when there is net movement of charge or non-zero current.
i) capacitors' plates are charged and an electric field exists between the plates.
Explanation:
soln,
weight=600N
mass=?
gravity=9.8 m/s²
now,
- mass=weight/gravity
- mass=600/9.8
- mass=61.22kg
hope it helps.
<h2>stay safe healthy and happy.</h2>
Answer:
Increase by a factor of 4.
Explanation:
The acceleration of a car moving with speed v in a circle of radius R is given by:
Now if we double the speed 
in the equation above, it becomes 
. Thus:
Therefore the acceleration is increased by a factor of 4.
Answer:
1.7 L
Explanation:
PV = nRT
If P, n, and R are constant:
V₁ / T₁ = V₂ / T₂
(2.0 L) / (293.15 K) = V / (255.15 K)
V = 1.7 L
