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Radda [10]
3 years ago
10

limestone chips dissolve after they are placed in a beaker of dilute acid. Which geologic process is this most similar to?

Physics
1 answer:
Nastasia [14]3 years ago
3 0
<span>Limestone chips dissolve after they are placed in a beaker of dilute acid Which geologic process is this most similar to weathering.</span>
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Need answer ASAP!!!
Alina [70]

Hello!

Use <u>ohm law:</u>

I = V / R

Replacing:

I = 100 V / 20 O

I = 5 A

The current is <u>5 amperes.</u>

5 0
3 years ago
15newtons is used to push a box along the floor a distance of 3 meters. How much work was done
tatuchka [14]

WD = f * d

WD = 15 * 3

WD = 45 J

8 0
3 years ago
8) As an object’s mass increases, its _________________ increases.
Andreyy89

as an object's mass increases , its "acceleration" increases

7 0
3 years ago
Read 2 more answers
in a car moving at constant acceleration, you travel 230 mm between the instants at which the speedometer reads 40 km/hkm/h and
Ronch [10]

The acceleration of the car is 0.8049m/s^{2}.It takes 13.802s to travel the 230 m.

<h3>What is acceleration?</h3>

In mechanics, acceleration refers to the rate at which an object's velocity with respect to time varies. Acceleration is a vector quantity (in that they have magnitude and direction). The direction of an object's acceleration is determined by the direction of the net force acting on it. Newton's Second Law states that the combined effect of two factors determines how much an item accelerates: 

(i) It follows that  the magnitude of the net balance of all external forces acting on the object is directly proportional to the magnitude of this net resulting force, and

(ii) the mass of the thing, depending on the materials out of which it is constructed, is inversely proportional to the mass of the thing.

Calculations:

40 km/hr ----- 11.11m/s

80 km/hr ----- 22.22m/s

v^{2} -u^{2} =2as\\22.22^{2} - 11.11^{2} = 2 x a x 230\\ 370.296=460a\\ a= 0.8049m/s^{2} \\

Time taken

v-u=at

22.22-11.11= 0.8049 x t

t=13.802s

To learn more about acceleration ,visit:

brainly.com/question/2303856

#SPJ4

4 0
2 years ago
A catapult with a radial arm 3.81 m long accelerates a ball of mass 18.2 kg through a quarter circle. The ball leaves the appara
saw5 [17]

Answer:

(a)\alpha = 53.73 m/s^2

(b)   I =428 kgm^2

(c)\tau = 428 \times 53.73  = 22996 .44Nm

Explanation:

GIVEN

mass = 18.2 kg

radial arm length = 3.81 m

velocity = 49.8 m/s

mass of arm = 22.6 kg

we know using relation between linear velocity and angular velocity

\omega = \frac{v}{l}

\omega = \frac{49.8}{3.81} \\\omega = 12.99 rad/s

for  angular acceleration, use the following equation.

\omega _{f}^2 = \omega_{i}^2+2\alpha\theta

since \omega _{i} = 0

here  for one circle is 2 π radians.   therefore for one quarter of a circle is π/2 radians

so   for one quarter \theta = \frac{\pi }{2}

(12.99)^2 = 2\alpha(\frac{\pi }{2})

on solving

\alpha = \frac{168.74}{\pi }\\\alpha = 53.73 m/s^2

(b)

For the catapult,

moment of inertia

I = \frac{1}{2}MR^2

I = \frac{1}{2} \times 22.6\times 3.81 \times 3.81\I = 164kg m^2

For the ball,

I = MR^2

I = 18.2 \times 14.51

I = 264 kgm^2

so total moment of inertia =  428 kgm^2

(c)

\tau = I\alpha

\tau = 428 \times 53.73  = 22996 .44Nm

3 0
4 years ago
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