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ratelena [41]
4 years ago
7

Please help ! It would be very much appreciated

Mathematics
1 answer:
stellarik [79]4 years ago
7 0

Answer:

I think it's 150%

$75-$30=$45

percentage increase=increase out of original amount x 100

\frac{30}{45}  \times 100

=150%

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3

Step-by-step explanation:

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Unit 8: Right Triangles &amp; Trigonometry<br> Homework 2: Special Right Triangles
Vsevolod [243]

Answer:

Part 1) x=14\sqrt{2}\ units

Part 2) y=14\ units

Part 3) z=14\sqrt{3}\ units

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ABC

we know that

The triangle ABC is a 45^o-90^o-45^o

so

Is an isosceles right triangle

The legs are equal

therefore

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x=14\sqrt{2}\ units

step 2

Find the length side BC

Applying the Pythagorean Theorem]

BC^2=AB^2+AC^2

BC^2=(14\sqrt{2})^2+(14\sqrt{2})^2

BC^2=784\\BC=28\ units

step 3

Find the value of y

In the right triangle BCD

sin(30^o)=\frac{BD}{BC} ----> by SOH (opposite side divided by the hypotenuse)

sin(30^o)=\frac{y}{28}

Remember that

sin(30^o)=\frac{1}{2}

so

\frac{y}{28}=\frac{1}{2}\\\\y=14\ units

step 4

Find the value of z

In the right triangle BCD

cos(30^o)=\frac{DC}{BC} ----> by CAH (adjacent side divided by the hypotenuse)

cos(30^o)=\frac{z}{28}

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cos(30^o)=\frac{\sqrt{3}}{2}

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\frac{z}{28}=\frac{\sqrt{3}}{2}\\z=14\sqrt{3}\ units

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nika2105 [10]

Answer:

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valina [46]

To find the shaded area in an image first calculate the total area of the figure and then subtract the white area from this total.

<h3>How to find the area of a shaded area?</h3>
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Note: This question is incomplete because the image of the shaded regions is not provided; due to this, the answer is based on general knowledge.

Learn more about triangles in: brainly.com/question/2773823

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