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Ugo [173]
3 years ago
12

Help please on this,

Mathematics
2 answers:
nikdorinn [45]3 years ago
6 0

Answer:

well one for adding, subtracting, multiplying, and dividing. (A) 160 (S) 80 (M) 4800 (D) 3

Step-by-step explanation:

As said above add, subtract, multiply, and divide

n200080 [17]3 years ago
5 0

Answer:

what is this?

Step-by-step explanation: you need to give use a better exlanation of the problem

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The average fine for entering a national Forest wilderness without a permit increased from $65 to $78. What rate of increase is
andrezito [222]

20%

A change from 65 to 78 represents a positive change (increase) of 20%

Use the formula found below to find the percent change by replacing the given values:

Percent change = [(New - Old ) / |Old|] x 100%


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In a week, 15 hens laid 75 eggs. what is the unit rate for eggs per hen?
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4 years ago
8.52 The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches
sweet [91]

Answer:

Heights of 29.5 and below could be a problem.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.

This means that \mu = 32, \sigma = 1.5

There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.

Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus

Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 32}{1.5}

X - 32 = -1.645*1.5

X = 29.5

Heights of 29.5 and below could be a problem.

4 0
3 years ago
Determine the intercepts of the line.<br> 4x – 1= 3y + 5<br> x-intercept:(_,_)<br> y-intercept:(_,_)
BARSIC [14]

Answer:

X-intercept: (1.5,0)

y-intercept: (0,-2)

the 1.5 can also be written as 3 over 2 in fraction form.

Hope this helps! :)

4 0
3 years ago
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