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ValentinkaMS [17]
3 years ago
13

17c-10=4 ............................

Mathematics
1 answer:
Katarina [22]3 years ago
7 0

Answer:

1.214 or 1\frac{3}{14} or \frac{17}{14}

Step-by-step explanation:

To solve this equation, first you need to the variable term isolated. You do this by adding 10 to each side. Your equation will now look like

17c = 14

Next, you will divide both sides by the 17.

Your equation now is solved, and above, I put ther three different forms for your answer: decimal, mixed number, and improper fraction.

~theLocoCoco

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Step-by-step explanation:

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2 years ago
The quotient rule for exponents states that bm bn=​_______, b≠0 . When dividing exponential expressions with the same nonzero​ b
wariber [46]

Answer:

The quotient rule for exponents states that b^{m}\div b^{n}=b^{m-n}.

When dividing exponential expressions with the same nonzero​ base, <u>subtract</u> the exponents.

Step-by-step explanation:

Some rules to solve exponents are:

  • x^{0}=1
  • (x^{m})^{n}=x^{mn}
  • x^{-n}=\frac{1}{x^{n}}
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  • \frac{x^{m}}{x^{n}}=x^{m-n}

The quotient rule for exponents states that:

b^{m}\div b^{n}=b^{m-n}.

When dividing exponential expressions with the same nonzero​ base, <u>subtract</u> the exponents.

3 0
3 years ago
Excuse me but can someone help me with this I have to do it before tomorrow
Vedmedyk [2.9K]

Answer:

8)  Onaje is correct

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Step-by-step explanation:

Paula is not correct because 16t + 9t ≠ 16 + 9 + 2t

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4 0
3 years ago
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What is 2+2+9+0+8+1+2+3+4+5+6+7+8+9
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6 0
2 years ago
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Write an equation of the line that passes through the given points.<br> (-1,5) and (2, - 7)
Vanyuwa [196]

Answer:

The equation of the straight line is 4x +y = 1

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given points are (-1,5) and ( 2,-7)

Slope of the line

m =\frac{y_{2}-y_{1}  }{x_{2} -x_{1} }  =\frac{-7-5}{2-(-1)}  = \frac{-12}{3} = -4

slope of the line m = -4

<u><em>Step(ii):-</em></u>

The equation of the straight line passing through the point (-1,5) and having slope 'm' = -4

y - y_{1} = m( x-x_{1} )

y - 5 = -4 ( x-(-1))

y -5 = -4 x -4

4 x + y -5 +4=0

4x +y -1 =0

<u><em>Final answer:-</em></u>

The equation of the straight line is 4x +y = 1

<u><em>  </em></u>

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