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levacccp [35]
3 years ago
12

i walked 3y - 2c + 600 meters yesterday. today, i walked 10,000 meters. how many more miles did i walk today?

Mathematics
1 answer:
Leokris [45]3 years ago
8 0
To find out how much more you walked today, you want to find the difference between the two days, which is 10,000-(<span>3y - 2c + 600) = 9400-3y+2c using the distributive property (the negative sign in front of the parenthesis is essentially a -1)</span>
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He nine ring wraiths want to fly from barad-dur to rivendell. rivendell is directly north of barad-dur. the dark tower reports t
kiruha [24]

This problem is better understood with a given figure. Assuming that the flight is in a perfect northwest direction such that the angle is 45°, therefore I believe I have the correct figure to simulate the situation (see attached).

 

Now we are asked to find for the value of the hypotenuse (flight speed) given the angle and the side opposite to the angle. In this case, we use the sin function:

sin θ = opposite side / hypotenuse

sin 45 = 68 miles per hr / flight

flight = 68 miles per hr / sin 45

<span>flight = 96.17 miles per hr</span>

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3 years ago
MATH HELP
Dmitry_Shevchenko [17]

Answer:

1.75 miles

Step-by-step explanation:

If he rides around his block 3 times it is 1.5 miles and if he only rides around his block half-way not a time it is a quarter of a mile added on instead of a half.

6 0
3 years ago
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Evelyn packed this box with 1-inch cubes. Which expression does NOT show how Evelyn can find the volume of the box?
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Answer:

2+3+6 is the incorrect expression

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3 years ago
The point (-2, 4) is plotted on the coordinate plane.
Masteriza [31]

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Step-by-step explanation:

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3 years ago
Find number a and k so that x-2 is afactor<br>OF F(x)=x4-2ax tax-<br>X+k and F(-1)=3​
Slav-nsk [51]

Question:

Find numbers a and k so that x-2 is a factor of

f(x)=x^4-2ax^3+ax^2- x+k

and

f(-1)=3

Answer:

k = -2 and a=1

Step-by-step explanation:

Given

f(x)=x^4-2ax^3+ax^2- x+k

Factor:\ x - 4

f(-1)=3

Required

Find a and k

For f(-1)=3

Substitute -1 for x

f(x)=x^4-2ax^3+ax^2- x+k

f(-1) = (-1)^4 - 2a *(-1)^3 + a*(-1)^2 - (-1) + k

f(-1) = 1 - 2a *-1 + a*1 +1 + k

f(-1) = 1 +2a + a +1 + k

f(-1) = 2 +3a + k

Substitute 3 for f(-1)

3 = 2 +3a + k

Collect Like Terms

3 - 2 = 3a + k

1 = 3a + k

Also:

If x - 2 is a factor, then

f(2) = 0

Substitute 2 for x and 0 for f(x)

f(x)=x^4-2ax^3+ax^2- x+k

0 = 2^4 - 2a * 2^3 + a * 2^2 - 2 + k

0 = 16 - 2a * 8 + a * 4 - 2 + k

0 = 16 - 16a + 4a - 2 + k

0 = 16 - 12a - 2 + k

Collect Like Terms

2 - 16 = - 12a + k

-14 = k - 12a

k = 12a - 14

Substitute 12a - 14 for k in 1 = 3a + k

1 = 3a + 12a - 14

1 = 15a - 14

Collect Like Terms

15a = 1 + 14

15a = 15

Solve for a

a = \frac{15}{15}

a=1

Substitute 1 for a in k = 12a - 14

k = 12 * 1 - 14

k = 12 - 14

k = -2

3 0
2 years ago
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