Answer:
I wont tell you the answer but I can tell you how to solve this one.
Step-by-step explanation:
If they are both squared then square them. Once you have the hypotenuse and the leg squared subtract the leg from the hypotenuse. That's your answer. Then you un- square it by finding the square root of the new number. That square root is your answer
Answer:
Step-by-step explanation:
time to cross will be the distance divided by the velocity in that direction.
a) t = d/v = 45/2.75 = 16.363636... 16.4 s
In the same time that the otter is swimming cross stream, the stream is also moving perpendicularly at its own pace.
b) d = vt = 2.5(16.36) = 40.9090... 40.9 m
As velocity is a vector, An observer on the bank would see the velocity as the vector addition of the cross stream and down stream velocities
c) v = √(2.75² + 2.5²) = 3.716517... 3.72 m/s magnitude
θ = arctan2.5/2.75 = 42.2736... 42.3° downstream of a line straight across
Answer:
15 minutes
There are 20 quarter hours in 5 hours. This is solved by first breaking down an hour into quarters. A quarter is 1/4 of an hour, or 15 minutes.
Use the Pythagorean theorem, tan is y/x so y = -3 and x= -2. Because cos is negative and R is always positive. You need to find R- which is the hypotenuse;
3^2 + 2^2 = r^2
9 + 4 = r^2
13 = r^2
√13 = r.
So you already have tan<span>θ,
cot</span><span>θ= 2/3
sin</span>θ= -3/√13 BUT
you have to rationalize, so you get -3 √13/ 13
cscθ= √13/ -3
cosθ= -2/ √13 BUT
you have to rationalize, so you get -2√13/ 13
secθ= √13/ -2
