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3 years ago

9

A train traveled from Chicago il to Los Angeles ca in 1 day and 15 minutes. This distance between the two cities is 20153 miles.

How fast was the train going on average

1 answer:

fgiga [73]3 years ago

4 0

831.05, I think that is the correct answer

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Tim tradesman had a taxable income of $82,500

maria [59]

What is the question?

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3 years ago

Need help fast please thanks

murzikaleks [220]

Answer:

c = 41 ft

Step-by-step explanation:

To solve this problem, we can use the pythagorean theorem, which is defined by the formula $a^2+b^2=c^2$ . We are given both the lengths of the legs, so all we need to do is to plug them both in and solve for c:

$9^2+40^2 = c^2\\c^2 = 81 + 1600\\c^2 = 1681\\c = 41$

This is the first option.

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3 years ago

Someone please give me the simplified answer !

Nataly [62]

Answer:

11m-3v

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Una funzione inversamente proporzionale è rappresentata da?

puteri [66]

Supponiamo che due variabili x e y siano inversamente proporzionali; allora possiamo rappresentarli come x ∝ 1 / y. Ciò significa che se il valore di x aumenta, il valore di y diminuisce e viceversa.

Suppose two variables x and y are inversely proportional; then we can represent them as x ∝ 1/y. That means, if the value of x increases, then the value of y decreases and vice versa.

3 0

2 years ago

Mike just hopped on the edge of a merry-go-round. What are his linear and angular speeds if the diameter of the merry-go-round i

dsp73

Step-by-step explanation:

Given that,

The diameter of the merry-go-round, d = 14 feet

Time taken, t = 6 seconds

Radius, r = 7 feet

The linear speed of the merry-go-round is given by :

$v=\dfrac{2\pi r}{t}\\\\v=\dfrac{2\pi \times 7}{6}\\\\=7.33\ m/s$

Also,

$v=r\omega$

Where

$\omega$ is the angular speed

So,

$\omega=\dfrac{v}{r}\\\\\omega=\dfrac{7.33}{7}\\\\=1.04\ rad/s$

Hence, his linear and angular speeds are 7.33 m/s and 1.04 rad/s.

8 0

3 years ago