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lawyer [7]
3 years ago
15

The cost of 11 dvds and 7 cds is 172.50 and the cost of 10 dvds and 7 cds is 155.80. How much does a cd and dvd cost?

Mathematics
1 answer:
AleksandrR [38]3 years ago
5 0

Answer:

The question has a mistake

Step-by-step explanation:

11d+7c= 172.5

10d+7c= 155.8

By subtraction;

1d+ 0c = 16.7

1d = 16.7

11×16.7+7c=172.5

7c = 172.5-11*16.7

You will get a negative answer yet the cost cannot be negative.

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Solve and check the linear equation 3x+2=x+6
Veseljchak [2.6K]
3x+2=x+6
subtract x from both sides,subtract 2 from both sides, gives you 2x=4,then divide by 2 on both sides and x will equal 2. Input the 2 for x and see if it will graph in a straight line on a graph.
4 0
4 years ago
Essential: Solve the proportions<br> step by step ​
vazorg [7]

Answer:

The value of r=\frac{-106}{47}

The value of x=\frac{83}{32}

Step-by-step explanation:

Given that,

A) \frac{2r-2}{7r+10} = \frac{9}{8}

Now,

\frac{2r-2}{7r+10} = \frac{9}{8}

8(2r-2)=9(7r+10)

16r-16=63r+90

-16-90=63r-16r

-(16+90)=47r

-106=47r

r=\frac{-106}{47}

B) \frac{x+4}{9} = \frac{3(x-2)-1}{5}

Now,

\frac{x+4}{9} = \frac{3(x-2)-1}{5}

5(x+5)=9[3(x-2)-1]

5x+25=9[3x-6-1]

5x+25=9[3x-7]

5x+25=27x-63

25+63=27x+5x

83=32x

x=\frac{83}{32}

6 0
4 years ago
Two objects in outer space drift apart at an average rate of 25 kilometers every year. if the objects continue to drift apart fr
arlik [135]

<u>The </u><u>distance </u><u>between the two objects in 10 years will be </u><u>250 kilometers.</u>

What is Distance?

Distance is the total movement of an object without any regard to direction. We can define distance as to how much ground an object has covered despite its starting or ending point.

We are given:

The rate at which two objects drift apart in 1 year = 25 km

To calculate the distance between the two objects in 10 years, we apply unitary method:

The distance, the two objects has drifted apart in 1 year is 25 km

So, the distance, the two objects has been drifted apart in 10 years, will be = \frac{25}{1} * 1 = 250 Km

Therefore, the distance between the two objects in 10 years will be 250 kilometers.

Learn more about distance

brainly.com/question/15172156

#SPJ4

3 0
1 year ago
A population of fish starts at 8,000 and decreases by 6% per year. what is the population of fish after 10 years?
ladessa [460]

Answer:

4308 fish

Step-by-step explanation:

Well you can just look at the answer and tell

14327 is not possible at all, thats an increase

839 is way too low

7680 doesn't make sense at all

4,309 is the most reasonable

6 0
3 years ago
Read 2 more answers
Kiara estimated that 45 customers bought fruit at her farm stand one day. The actual number of customers who bought fruit was 41
Reil [10]
So if she estimated 45 and has 41, then the error is 45-41=4

so find what percent=4/45
divide
4/45=0.0888888
percent=parts out of 100 so
x/100=x%

so 0.0888/1 times 100/100=8.8888/100
the answer is 8.88888% or rounded up is 8.9%
the answer is C
7 0
3 years ago
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