<span>XY=11d\ YZ=9d-2\ \ xz=5a+22
</span>D = 2 YZ = 16
Step-by-step explanation:
The area = 3 × 10 = 30
The perimeter = 2(3 + 10) = 26
please give me a brainliest answer
Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.
Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A
Applying that here:
40^2 = 32^2 + 64^2 - 2(32)(64)cos Q
Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.
The picture is to blurry sorry
