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Radda [10]
2 years ago
10

Gretchen made a paper cone to hold a gift for a friend. The paper cone was 14 inches high and had a

Mathematics
2 answers:
LUCKY_DIMON [66]2 years ago
8 0

Answer:

268.0 in²

Step-by-step explanation:

refer to attached graphic as reference

volume of cone, V = (1/3) πr²h

in our case, we are given r = 4" and h = 16"

substituting this into equation:

V = (1/3) πr²h

=  (1/3) ·(3.14) · (4)²· (16)

= 267.94667 in²

= 268.0 in² (nearest tenth)

Novay_Z [31]2 years ago
8 0
268.0 in^2 hope this helps
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hammer [34]
2nd one maybe I’m not to sure srry
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3 years ago
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A wedge of cheese is shaped like a triangular prism. The wedge of cheese is 7 inches tall. The base of the cheese is shaped like
Gala2k [10]

Answer:

193 in

Step-by-step explanation:

Volume of a triangular prism:

The volume of a triangular prism is the base area multiplied by the wedge, that is:

V = A_bw

The base area is one half times the triangle base times it's height, so:

V = 0.5*b*h*w

The wedge of cheese is 7 inches tall.

This means that w = 7

The base of the cheese is shaped like a triangle with a base of 11 and a height of 5 inches.

This means that b = 11, h = 5

Volume:

V = 0.5*b*h*w = 0.5*11*5*7 = 192.5

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4 0
3 years ago
Gradient from 2 - 1/2y = 0​
kirill115 [55]

Given :

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To find :-

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4 0
2 years ago
Given that the expression 2x^3 + mx^2 + nx + c leaves the same remainder when divided by x -2 or by x+1 I prove that m+n =-6
Alla [95]

Given:

The expression is:

2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1.

To prove:

m+n=-6

Solution:

Remainder theorem: If a polynomial P(x) is divided by (x-c), thent he remainder is P(c).

Let the given polynomial is:

P(x)=2x^3+mx^2+nx+c

It leaves the same remainder when divided by x -2 or by x+1. By using remainder theorem, we can say that

P(2)=P(-1)              ...(i)

Substituting x=-1 in the given polynomial.

P(-1)=2(-1)^3+m(-1)^2+n(-1)+c

P(-1)=-2+m-n+c

Substituting x=2 in the given polynomial.

P(2)=2(2)^3+m(2)^2+n(2)+c

P(2)=2(8)+m(4)+2n+c

P(2)=16+4m+2n+c

Now, substitute the values of P(2) and P(-1) in (i), we get

16+4m+2n+c=-2+m-n+c

16+4m+2n+c+2-m+n-c=0

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3m+3n=-18

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7 0
2 years ago
A student is asked to find the length of the hypotenuse of a right triangle. The length of one leg is 34
VikaD [51]

Answer:

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Step-by-step explanation:

The right triangle formula: c^2 = a^2 + b^2

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                                  a and b are the legs of the triangle.    

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                                          c = square root of ( 576 + 1,156)

                                          c = 41.6173

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2 years ago
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