Answer:
x = 4, TU = 22
Step-by-step explanation:
Given that TS bisects TU at Q , then
TQ = QU , substitute values
5x - 9 = 15 - x ( add x to both sides )
6x - 9 = 15 ( add 9 to both sides )
6x = 24 ( divide both sides by 6 )
x = 4
Thus
TU = 5x - 9 + 15 - x = 4x + 6 = 4(4) + 6 = 16 + 6 = 22
Rectangle A’B’C’D’ has a scale factor of 2 because it is two times bigger then the original rectangle ABCD after the dilation.
Answer:
≈ 7.6
Step-by-step explanation:
Calculate the distance using the distance formula
d = √ (x₂ - x₁ )² + (y₂ - y₁ )²
with (x₁, y₁ ) = (- 1, - 1) and (x₂, y₂ ) = (6, 2)
d = 
= 
= 
= 
≈ 7.6 ( to the nearest tenth )
Answer: x - 2.6 = 72.8
x is the number which Dan was thinking (x > 2.6)
we have:
x - 2.6 = 72.8
Step-by-step explanation:
<span>This is an java command program.
String 1 is stands for str1= '' forest '' accepted within quote marks.
String 2 is stands for str1= '' school'' accepted within quote marks
the command compareto will cause the output will display as shown below :
str1.compareto(str2); when run this command
we will get the output like this ;
forest
school
==================================================
the model program is like this;
{
String str1 = " forest " ;
String str2 = "school ";
System.out.println();
System.out.println("String 1: " + str1);
System.out.println("String 2: " + str2);</span>
