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valentina_108 [34]
3 years ago
5

What set of values could be the side lengths of 30-60-90 triangles

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
5 0

Answer:

4

Step-by-step explanation:

You might be interested in
3∣a−b∣ if a=−9 and b=3
yKpoI14uk [10]

Answer:

36 because the absolute value of -9-3 is 12, and then 12 times 3 is 36

8 0
2 years ago
3.
Gwar [14]

Answer:

x = 3  and  x = -3

Step-by-step explanation:

In this problem, we are substituting for x.

Let us take a look at our given answers.

x = -13 and x = -3 would not work because the numbers would not add up to -5. Since we have the positive brackets (or whatever you call them.) surrounding the x variable, that means that all numbers that are plugged into x will be positive.

-13 will be turned into 13,

13 - 8  \neq  -5

So that is wrong.

x = 3 and x = 3 would work because plugging it in, all outcomes from the two numbers would be negative.

3 - 8 = -5

|-3|  - 8 = -5

True.

The third one won't work because of the same reasons as the first one.

Then, the last one would not work well because, there is a solution.

4 0
3 years ago
If the area of a right triangle is 9/16 sq. ft. and the height is 3/4 ft, write an equation that relates the area to the base,b,
Rudik [331]

Answer:

Base = 1.5 ft

Step-by-step explanation:

Area = ½ × base × height

9/16 = ½ × base × 3/4

9/16 = 3/8 × base

base = 9/16 × 8/3

base = 3/2

base = 1½ ft

5 0
3 years ago
A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses
Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

                    Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = average age of the random sample of horses with colic = 12 yrs

            \mu = average age of all horses seen at the veterinary clinic = 10 yrs

   \sigma = standard deviation of all horses coming to the veterinary clinic = 8 yrs

         n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(\bar X \geq 12)

   P(\bar X \geq 12) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \geq \frac{12-10}{\frac{8}{\sqrt{60} } } ) = P(Z \geq 1.94) = 1 - P(Z < 1.94)

                                                 = 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0
3 years ago
A) 2 x -7 =<br>b) -3 x 4 =<br>c) -5 % -6 =​
erastovalidia [21]

Answer:

a)2×-7= -14

b)-3×4= -12

c)-5%+6= -6.05

8 0
3 years ago
Read 2 more answers
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