What set of values could be the side lengths of 30-60-90 triangles
1 answer:
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Answer:
Step-by-step explanation:
In this problem, we are substituting for x.
Let us take a look at our given answers.
x = -13 and x = -3 would not work because the numbers would not add up to -5. Since we have the positive brackets (or whatever you call them.) surrounding the x variable, that means that all numbers that are plugged into x will be positive.
-13 will be turned into 13,
13 - 8 -5
So that is wrong.
x = 3 and x = 3 would work because plugging it in, all outcomes from the two numbers would be negative.
3 - 8 = -5
- 8 = -5
True.
The third one won't work because of the same reasons as the first one.
Then, the last one would not work well because, there is a solution.
Answer:
Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.
Step-by-step explanation:
We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.
So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;
Z = ~ N(0,1)
where, = average age of the random sample of horses with colic = 12 yrs
= average age of all horses seen at the veterinary clinic = 10 yrs
= standard deviation of all horses coming to the veterinary clinic = 8 yrs
n = sample of horses = 60
So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(
12)
P(
12) = P(
) = P(Z
1.94) = 1 - P(Z < 1.94)
= 1 - 0.97381 = 0.0262
Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.