Ask question

Ask question

All categories

2 years ago

12

You have 1300 dollars to invest on mugs. Each mug is 2 dollars each after you put the logo you resell it for 7. Find the equatio

n for the printing the mugs

1 answer:

VashaNatasha [74]2 years ago

8 0

Answer:

2-1300+7m

Step-by-step explanation:

m=mugs

You might be interested in

Use the Distributive Property to solve the equation below. Use pencil and paper. Describe what it means to distribute the 2 to e

Bad White [126]

Answer:

Use the distributive property to solve the equation 2(m + 2) = 22. Describe what it means to distribute the 2 to each term inside the parentheses

8 0

2 years ago

Find the equation of the circle which passes through points <br>(3,-1), (3,9) and (-2,4)<br>

mash [69]

Y=-x+2

OR if you are looking for point slope:

y+1=-1(x-3)

6 0

2 years ago

HELP PLEASE ITS DUE TODAY!!! Express 14 hours in 2 weeks as a unit rate

user100 [1]

Answer:

14/336 ----------> 0.41

Step-by-step explanation:

you substituto 2 week to 336 cause there are 336 hours in 2 weeks therefore 14/336 = 0.41

the unit rate is 14/336

7 0

2 years ago

Solve the following systems of equations.<br> 2^(2x+y−1) = 32<br> 4^(x−2y) = 2

Rina8888 [55]

Answer:(x,y)=(2.5,1)

Step-by-step explanation:

Given

$2^{2x+y-1}=32$

$2^{2x+y-1}=2^5$

thus on comparing

2x+y=6------1

$4^{x-2y}=2$

$2^{2(x-2y)}=2$

On comparing exponent of 2

$x-2y=\frac{1}{2}$ ------2

we get x=2.5

substitute x in 1

y=1

(x,y)=(2.5,1)

6 0

2 years ago

Write a polynomial function of minimum degree in standard form with real coefficients whose zeros and their multiplicities inclu

Softa [21]

<u>Answer-</u>

<em>The polynomial function is,</em>

$y=x^4-10x^3+38x^2-64x+40$

<u>Solution-</u>

The zeros of the polynomial are 2 and (3+i). Root 2 has multiplicity of 2 and (3+i) has multiplicity of 1

The general form of the equation will be,

$\Rightarrow y=(x-(2))^2(x-(3+i))(x-(3-i))$ ( ∵ (3-i) is the conjugate of (3+i) )

$\Rightarrow y=(x-2)^2(x-3-i)(x-3+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)-i)((x-3)+i)$

$\Rightarrow y=(x^2-4x+4)((x-3)^2-i^2)$

$\Rightarrow y=(x^2-4x+4)((x^2-6x+9)+1)$

$\Rightarrow y=(x^2-4x+4)(x^2-6x+10)$

$\Rightarrow y=x^2x^2-6x^2x+10x^2-4x^2x+4\cdot \:6xx-4\cdot \:10x+4x^2-4\cdot \:6x+4\cdot \:10$

$\Rightarrow y=x^4-10x^3+14x^2+24x^2-40x-24x+40$

$\Rightarrow y=x^4-10x^3+38x^2-64x+40$

Therefore, this is the required polynomial function.

4 0

3 years ago