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Marat540 [252]
4 years ago
15

What’s the area of this shape

Mathematics
2 answers:
Step2247 [10]4 years ago
5 0

Split this shape into a trapezoid and a triangle


Area of trapezoid:

A = 1/2(b1+b2)h

A = 1/2(4+8) (2)

A = 12


Area of triangle:

A = 1/2bh

A = 1/2(8)(5.75)

A = 23


Area of the shape = Area of trapezoid + Area of triangle

= 12 + 23

= 35


Answer

35 cm^2

sergeinik [125]4 years ago
3 0

The shape at the top is a trapezoid with width 2 cm and lengths 4 and 8 cm.

Its area is


4+8

-------- 2 cm = 12 cm^2

2


The lower part consists of two congruent triangles. The area of a triangle is

A = (1/2)(b)(h). Here, A = (1/2) (4)(5.75) = 11.5, so the area of both triangles is 23 cm^2.


Thus, the total area is (12+23) cm^2, or 35 cm^2.

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Step-by-step explanation:

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3 years ago
12. I don’t know how to do it
Nostrana [21]

Answer:

BC = 50

Step-by-step explanation:

I believe what I'm doing is correct but to be completely honest with you, I haven't done this in a while lol

Okay so...

You would do

1. 6y-16 = 4y+6

You would subtract 4 from 6...

2. 2y-16 = 6

You would then add 16 to 6...

3. 2y = 22

Then, divide 2 from 22...

4. y = 11

Substitute into BC...

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Then, you get your final answer...

6. BC = 50

I hope it's right. Good luck ^^

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3 years ago
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A blimp is flying at a speed of 40mph and going in a direction of 80 degrees. After 3 hours of flying it turns and travels 1 hou
kykrilka [37]

Bearing is a topic that can be used to <u>locate</u> the <em>position</em> of an object at a given time. Therefore, the blimp is <em>80 m</em> far away from its <u>starting</u> point. And in the<em> North-East </em>direction.

The <u>speed</u> of an object relates the <em>distance</em> it covers to the <u>time taken</u> to cover the said distance.

i.e speed = \frac{distance}{time taken}

⇒ distance = speed x time taken

In the given question, the <u>initial</u> distance covered can be determined as;

distance = 40 mph x 3 h

              = 120 m

The<u> final </u>distance covered can be determined as;

distance = 40 mph x 1 h

              = 40 m

Let the <u>distance</u> from its <em>starting</em> point to its <em>fina</em>l location be represented by x.

Thus applying the<em> Cosine rule</em>, we have:

c^{2} = a^{2} + b^{2} - 2abCos C

x^{2} = 120^{2} + 40^{2} - 2(120 x 40) Cos 90

   = 14400 + 1600 - 9600

x^{2} = 16000 - 9600

   = 6400

x = \sqrt{6400}

 = 80

x = 80 m

Therefore, the <u>distance</u> of the blimp from its <em>starting</em> point to its <em>final</em> destination is <u>80 m</u>.

For more clarifications on bearings, visit: brainly.com/question/22979472

#SPJ1

6 0
3 years ago
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