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Natalija [7]
3 years ago
8

How to differentiate?? and what rule should be applied here? thanks in advance! :)

Mathematics
1 answer:
andrezito [222]3 years ago
4 0
You could write this as

x(x^2-1)^{-1/2}

Then by the product rule, the derivative is

(x(x^2-1)^{-1/2})'=x((x^2-1)^{-1/2})'+(x)'(x^2-1)^{-1/2}=x\left(-\dfrac12(x^2-1)^{-3/2}(2x)\right)+(x^2-1)^{-1/2}
\left(\dfrac x{\sqrt{x^2-1}}\right)'=-x^2(x^2-1)^{-3/2}+(x^2-1)^{-1/2}

Pulling out a factor of (x^2-1)^{-3/2}, the right hand side can be rewritten as

-(x^2-1)^{-3/2}\left(x^2-(x^2-1)^1\right)=-\dfrac1{(x^2-1)^{3/2}}
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