Question: Given that BE bisects ∠CEA, which statements must be true? Select THREE options.
(See attachment below for the figure)
m∠CEA = 90°
m∠CEF = m∠CEA + m∠BEF
m∠CEB = 2(m∠CEA)
∠CEF is a straight angle.
∠AEF is a right angle.
Answer:
m∠CEA = 90°
∠CEF is a straight angle.
∠AEF is a right angle
Step-by-step explanation:
Line AE is perpendicular to line CF, which is a straight line. This creates two right angles, <CEA and <AEF.
Angle on a straight line = 180°. Therefore, m<CEA + m<AEF = m<CEF. Each right angle measures 90°.
Thus, the three statements that must be TRUE are:
m∠CEA = 90°
∠CEF is a straight angle.
∠AEF is a right angle
Height=4 ft
angle=33 degrees
My tip first is to draw it out. Draw an acute angle opening up to a building forming a triangle. Inside of the vertex of the acute angle is the degree 33 and the height of the building is 4 ft. So, use trig! Do you have a calculator? Opposite over hypotenuse is Sine. (SOH CAH TOA). (4)/(sin(33)). which equals 7.34 ft as your height! Hope this helped!
Answer:
true
Step-by-step explanation:
the second 7 is in the tenth place and the first 7 is in the hundredth place, which is 1/10 the tenth place
Answer: 1/6
Step-by-step explanation:
Slope is the m in y=mx+b
Okay! I drew the graph and I got Point Q is 0.1 unit to the right of 1.
Knowing the order of the numbers is the best way to get the answer.