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ss7ja [257]
2 years ago
6

Samples of size n = 60 are randomly selected from the population of numbers (0 through 9) produced by a random-number generator,

and the mean is taken for each sample. What is the distribution of the sample means?
Mathematics
1 answer:
klemol [59]2 years ago
8 0

The distribution of the sample means when the samples of size n = 60 are randomly selected from the population is normal (approximately).

<h3>How is the sample explained?</h3>

Calculating the sample mean is as simple as adding up the number of items in a sample set and then dividing that sum by the number of items in the sample set.

Here, the distribution of the sample means when the samples of size n = 60 are randomly selected from the population is normal (approximately).

Learn more about samples on:

brainly.com/question/2838094

#SPJ1

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12. Write the equation of a parabola with vertex at<br> (2, -3) and focus at (2,5),
Tatiana [17]

Step-by-step explanation:

The basic form of equation:

(x-h)²=4a(y-k),

(h,k)=coordinates of vertex

(h, k+a) = coordinate of focus

For given parabola:

axis of symmetry: x=2

(h, k) =(2,-3)

(h, k+a)=(2,5)

k+a=5

-3+a=5

a=8(distance from vertex to focus on the axis of symmetry)

equation: (x-2)²=4×8(y+3)

(x-2)²= 32(y+3)

7 0
3 years ago
Triangle XYZ is reflected across the x-axis, and X = (–11, 8). What are the coordinates of X’ ?
valina [46]

9514 1404 393

Answer:

  (-11, -8)

Step-by-step explanation:

Reflection across the x-axis changes the sign of the y-coordinate.

For X(-11, 8), the reflected point is X'(-11, -8).    (matches the last choice)

5 0
3 years ago
Read 2 more answers
2 balls can complete a full rotation in 120 min. How many balls can complete a full rotation in 180 min
riadik2000 [5.3K]
Its 3, because each ball is 60 min each and 60 times 3 would get you 180
6 0
3 years ago
A population of 100 frogs increases at an annual rate of 22%. How many frogs will there be in 5 years? Write an expression to re
gizmo_the_mogwai [7]
Exponential growth of the form:

F=Ar^t

F=100(1.22)^t

F(5)=100(1.22)^5

F(5)=270.27

F(5)=270 to the nearest frog...

....

1.22=r^12

r=1.22^(1/12)

F=100(1.22^(1/12)^t)

F=100(1.22^(t/12))  now it will produce monthly populations...

Say we did the same as before but instead of 5 years you have 60 months...

F(60)=100(1.22^(60/12))

F(60)=270 to the nearest frog... :P 
6 0
3 years ago
Can any one help me
emmainna [20.7K]
I think you set up the equation like this

$2.50x+5

I hope I helped sorry if I didn't.

8 0
3 years ago
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