Answer:
0.47V
Explanation:
2 Al(s) + 3 Mn2+(aq) → 2 Al3+(aq) + 3 Mn(s)
n= 6 ( six moles of electrons were transferred)
Q= [Red]/[Ox] but [Red]= 1.5M, [Ox] = 0.12 M
Q= 1.5/0.12= 12.5
From Nernst equation:
E= E°cell- 0.0592/n log Q
E°cell= 0.48 V
E= 0.48 - 0.0592/6 log (12.5)
E= 0.47V
Answer:
The change from a liquid phase to a gaseous phase occurs when the vapor pressure of the liquid is equal to the atmospheric pressure exerted on the liquid.
Explanation:
Boiling is a physical change and molecules are not chemically altered during the process.
<u>Epipelagic </u>zones are warm, well lit, and have lots of marine life.
Explanation:
This is the topmost zone of the oceans extending about 200 meters from the ocean surface. This zone is well lit because sunlight is able to penetrate this layer before it discusses as it penetrates deeper into the ocean. Therefore, this epipelagic zone is able to sustain plankton (that are photosynthetic). Plankton form the base of marine life which is why they support a large marine ecosystem in the epipelagic zone and thie energy flow even to the deeper abyssopelagic zone.
<span>2 * 22.4 = 44.8 liters (if using pre 1982 standard)
2 * 22.7 = 45.4 liters (if using 1982 and later standard)
First, let's determine how many moles of F2 we have.
Atomic weight fluorine = 18.998403
Molar mass F2 = 2 * 18.998403 = 37.996806 g/mol
Moles F2 = 76 g / 37.996806 g/mol = 2.000168119 mol
Now we have a minor problem. What definition of STP are you using?
Up until 1982,
STP was defined as 0°C and 1 atmosphere (101.325 kPa)
From 1982 and later,
STP was defined as 0°C and 100 kPa
Because of the difference in pressure between the two different definitions of STP, the molar volume of a gas is 22.414 liter/mol using the pre-1982 definition and 22.711 liter/mol using the 1982 and later definition. So you get to choose which of the following 2 answers.
2 * 22.4 = 44.8 liters (if using pre 1982 standard)
2 * 22.7 = 45.4 liters (if using 1982 and later standard)
Unfortunately there's still a large number of text books in use using the standard that should have been obsolete 35 years ago.</span>
Answer:
The question is incomplete and confusing.
- In the complete ionic equation you write all the ions that are formed. Those are: Pb²⁺, NO₃⁻, K⁺, and I⁻. They all are present in the complete ionic equation.
- In the net ionic equation, the spectator ions do not appear. They are: NO₃⁻ and K⁺. They would not be present in the net ionic equation, but they do in the complete ionic equation.
See below the details.
Explanation:
Which compound will not form ions?
<u />
<u>1. Write the balanced molecular equation:</u>
- Pb(NO₃)₂(aq) + 2KI(aq) → PbI₂(s) + 2KNO₃(aq)
<u />
<u>2. Write the ionizations for the ionic aqueous compounds:</u>
<u />
- Pb(NO₃)₂(aq) → Pb⁺²(aq) + 2NO₃⁻(aq)
- 2KI(aq) → 2K⁺(aq) + 2I⁻(aq)
- 2KNO₃(aq) → 2K⁺(aq) + 2NO₃⁻(aq)
<u />
<u>3. Write the complete ionic equation:</u>
Pb⁺²(aq) + 2NO₃⁻(aq) + 2K⁺(aq) + 2I⁻(aq) → PbI₂(s) + 2K⁺(aq) + 2NO₃⁻(aq)
Hence, since PbI₂(s) does not ionize, but stays in solid form, it will not form ions.
All, Pb⁺², NO₃⁻, K⁺, and I⁻ will be present in the total ionic equation.
It is in the net ionic equation that the spectator ions are removed. Those, are NO₃⁻ and K⁺, because they are on both sides of the complete ionic equation.
