SOLUTION
We will use the formula
Applying we have
Now using a Zscore calculator for 1.370320, we have
P(xHence the answer is 0.9147
Use absolute value to express the distance between −10 and 16 on the number line.
2 answers:
You might be interested in
So to find the answer you have to know what the mixture is, what the trend is,
on day one he used 4 cans of blue and 6 cans of yellow
day two, 6 blue and 9 yellow
both are divisible by 2 and 3 respectively, additionally when you divide the number of blue cans Marc used by the number of yellow cans each day you get a sum of .66
those are the trends
so therefore day three would have the same trend.
Now on day three Marc will have 4 cans of blue paint and 5 cans of yellow paint remaining, what I did here to find the answer was divide numbers under 4 and 5 until I got a division problem that equaled .66
my answer was 2 blue cans and 3 yellow.
The answer is that on day three the highest number of cans that Marc can mix to get his favorite shade of green is 2 blue and 3 yellow
on day one he used 4 cans of blue and 6 cans of yellow
day two, 6 blue and 9 yellow
both are divisible by 2 and 3 respectively, additionally when you divide the number of blue cans Marc used by the number of yellow cans each day you get a sum of .66
those are the trends
so therefore day three would have the same trend.
Now on day three Marc will have 4 cans of blue paint and 5 cans of yellow paint remaining, what I did here to find the answer was divide numbers under 4 and 5 until I got a division problem that equaled .66
my answer was 2 blue cans and 3 yellow.
The answer is that on day three the highest number of cans that Marc can mix to get his favorite shade of green is 2 blue and 3 yellow
Answer:
Part 1: 43.75%
Part 2: 44.07%
Step-by-step explanation:
Hello!
(Pt.1) First, set up a ratio . Next, you use long division I got the percent 43.75. After that, you subtract 6 from the girls group, (because of them moving away and then more coming back.) and 2 from the boys group. Then, you subtract those from the school "population" and you get 472 as the final population. So then you set up another ratio,
. I got a percent of 44.07% from that.
Thanks For Reading!