The probability that demand is greater than 1800 gallons over a 2 hour period is : 0.5
<u>Given data :</u>
Mean value of gasoline per hour = 875 gallons
Standard deviation = 55 gallons
<h3>Determine the probability of demand being greater than 1800 gallons over 2 hours </h3>
Demand for gas in 1 hour = X₁
Demand for gas in 2 hours = X₁ + X₂
Therefore ; ( X₁ + X₂) ~ N ( u₁+u₂, sd₁² + sd₂² )
In order to calculate probabilities for normals apply the equation below
Z = ( X- u ) / sd
where : u = 1800, sd = √ ( 55² + 55² ) = 77.78
using the z-table
P( Y > 1800) = P( Z > ( 1800 - 1800 ) / 77.78)
= P( Z>0 ) = 0.5
Hence we can conclude that The probability that demand is greater than 1800 gallons over a 2 hour period is : 0.5.
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Answer: B
Explanation:
Therefor, value 2.659 is closest to the value of e
( I hope this helped of not I’m sorry)
Hello,
Here is your answer:
The proper answer is option A "true". It is extremely important to find the source of the information because the source could not be verified (which means its giving false information).
Your answer is A.
If you need anymore help feel free to ask me!
Hope this helps!
It can affect the company's ability to get a lending (borrow money). It can also affect the chances of finding an investor.
Answer: C. 0.3
Explanation: The Acceptable Macronutrient Distribution Range (AMDR) usually expressed as percentage of total daily intake of energy is defined as the range of intakes for a particular energy source (protein, fat, carbohydrate etc) that is associated with reduced risk of chronic disease while providing adequate intakes of essential nutrients required by the body. For proteins this is within the range of 10 to 35%, expressed as fraction, 0.1 to 0.35. Option C falls within this range and therefore is the correct answer.
