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Irina18 [472]
4 years ago
13

What is the value of z for the parallelogram shown? A.130 B.40 C.10 D.26

Mathematics
2 answers:
galben [10]4 years ago
7 0
Z=10 because the opposite side is 50 degrees so the 5z=50

If you solve, z=10
schepotkina [342]4 years ago
3 0

Answer:

The correct option is C. The value of z is 10.

Step-by-step explanation:

According to the property of parallelogram, then opposite interior angles of a parallelogram are equal.

From the given graph it is clear that in parallelogram ABCD, angle A and angle C are opposite interior angles.

Using the property of parallelogram,

\angle A=\angle C                 (opposite interior angles of a parallelogram)

5z^{circ}=50^{circ}

5z=50

Divide both sides by 5.

z=\frac{50}{5}

z=10

The value of z is 10. Therefore the correct option is C.

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\frac{9}{10} \div \frac{6}{7}
You just flip 6/7 so it would be 7/6 and then you times it.
\frac{9}{10} \div \frac{6}{7}
\frac{9}{10} \times \frac{7}{6} = \frac{63}{60} = \frac{21}{20} 

6 0
3 years ago
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Answer:

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Step-by-step explanation:

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6 0
3 years ago
A researcher is going to estimate the average typing speed of students of a college. He selects a random sample of 20 students a
Stella [2.4K]

Answer:

The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 20 - 1 = 19

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 1.7291

The margin of error is:

M = T\frac{s}{\sqrt{n}}

In which s is the standard deviation of the sample and n is the size of the sample. For this question, we have s = 5, n = 20. So

M = T\frac{s}{\sqrt{n}}

M = 1.7291\frac{5}{\sqrt{20}}

M = 1.933

The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.

8 0
3 years ago
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