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Naily [24]
3 years ago
15

Which problem would you use the following proportion to solve for? = What is 40% of 24? What percent is 24 of 40? Twenty-four is

40% of what number? Forty percent of 24 is what number?
Mathematics
2 answers:
wariber [46]3 years ago
6 0
"Forty percent of 24 is what number?" Is your answer.

Hope this helps!!
~Kiwi
enyata [817]3 years ago
6 0

Forty percent of 24 is what number? is the answer.

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Find the output, f, when the input, t, is 7.<br> f = 2t - 3f=2t−3
ella [17]

Answer:

f = 3 1/2

Step-by-step explanation:

f = 2t - 3f     Substitute 7 for t

f = 2(7) - 3f   Multiply

f = 14 - 3f

+3f     + 3f    Add 3f to both sides

4f = 14          Divide both sides by 4

f = 3 1/2

If this answer is correct, please make me Brainliest!

6 0
3 years ago
A growing farming conglomerate increases its water usage at a rate of 10% every year. If it
Elena-2011 [213]

The quantity of water the farming conglomerate would use 17 years from now is 65,708.11.

<h3>What is the amount of water that would be used 17 years from now?</h3>

The formula for calculating the amount of water that would be needed 1 years from now:

FV = P (1 + r)^N

  • FV = Future value
  • P = Present value
  • R = interest rate
  • N = number of years

13000 x 1.1^17 = 65,708.11

To learn more about future value, please check: brainly.com/question/18760477

8 0
2 years ago
Help! (math and area.) i'll give you brainliest!
Viefleur [7K]
Q.12

30-18=12
Answer =12
5 0
3 years ago
What 2 numbers add to get 2 and multiply to 4
rusak2 [61]
Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x=\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a} so

1x^2-2x+4=0
a=1
b=-2
c=4
x=\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}
x=\frac{ 2+/-\sqrt{4-16} }{2}
x=\frac{ 2+/-\sqrt{-12} }{2}
we have \sqrt{-12} and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x=\frac{ 2+/-2\sqrt{-3} }{2}
i=\sqrt{-1}
x=\frac{ 2+/-2i\sqrt{3} }{2}
x=1+/-i\sqrt{3}
x=1-i\sqrt{3} or x=1+i\sqrt{3} (those are the 2 numbers)

 





6 0
3 years ago
Dimension of triangle A are three times the dimensions of triangle
nikitadnepr [17]
<span>a I took the test on ingenuity</span>
8 0
3 years ago
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