820.681 in expanded form would look like this:
Answer:
b) One sample z-test for means
Step-by-step explanation:
Normal Distribution
we have μ₀ (population mean from previous studies)
sample size n = 100
standar deviation of population σ = 0.75
And it was determined from sample, that μ = 5 : so we want to know if, at some significance level that value (which is smaller than population mean ) could help in relation to decide about rejecting hypothesis H₀
We should use a z one tail-test for means (left tail)
B. It cant be A because a negative leading coefficient would mean it was turned facing down. It can't be C because the bottom of the loop is a turning point. It cant be C because it doesn't cross the x-axis.
Answer:
<h2>-8 + 11n OR 11n - 8</h2>
Step-by-step explanation:
an = 3 + (n-1)11
an = 3 + 11n - 11
an = -8 + 11n OR 11n - 8
Hope that helps!
Answer:
60
Step-by-step explanation:
