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ahrayia [7]
3 years ago
9

Estimate 0.5% of 600 Pls

Mathematics
1 answer:
saw5 [17]3 years ago
7 0

Answer:

300

Step-by-step explanation:

.5 is also known as 1/2

just divide by 2

600/2=300

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Bob took a total of 30 quizzes over the course of 5 weeks. After attending 8 weeks of school this quarter, how many quizzes will
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Answer:

Step-by-step explanation:

total= 5/8

8 0
3 years ago
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Point A' is the image of point A when point A is rotated about the origin B. What angle in the counterclockwise direction is
Elza [17]

9514 1404 393

Answer:

  90° CCW

Step-by-step explanation:

The slope of BA is -1/3. The slope of BA' is 3, so the slopes are opposite reciprocals of one another. These segments are perpendicular, meaning the angle between them is 90°.

Point A' has been rotated 90° CCW about point B.

8 0
3 years ago
I need help with question a and b
DaniilM [7]

Solving for part A

f(x) = x^{2} \;\;and\;\; g(x) = \frac{1}{x^{3}} \\\\f(g(x)) = (\frac{1}{x^{3}})^{2}   =\frac{1}{x^{6}}

Domain of composition: x ≠ 0 i.e. Domain is the set of "Real numbers excluding number 0".

Solving for part B

f(x) = \frac{x}{x-2}\;\;and\;\;g(x) =\frac{3}{x} \\\\f(g(x))=\frac{\frac{3}{x}}{\frac{3}{x}-2}=\frac{\frac{3}{x}}{\frac{3-2x}{x}} =\frac{3}{3-2x}\\\\  Domain:\;3-2x\neq  0 \;\;OR\;\;x\neq \frac{3}{2}

5 0
4 years ago
The time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a
AlekseyPX

Answer:

The time that the boys need to beat in order to earn a certificate of recognition from the fitness association is 511.264 seconds.

Step-by-step explanation:

We are given that the time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a standard deviation of 40 seconds.

The fitness association wants to recognize the fastest 10% of the boys with certificates of recognition.

<u><em>Let X = time for this event for boys in secondary school</em></u>

SO, X ~ Normal(\mu=460,\sigma^{2} =40^{2})

The z-score probability distribution for normal distribution is given by;

                               Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = mean time = 460 seconds

            \sigma = standard deviation = 40 seconds

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

<u>Now, it is given that the fitness association wants to recognize the fastest 10% of the boys with certificates of recognition, which means;</u>

       P(X > x) = 0.10   {where x is the required time which boy need to beat}

       P( \frac{X-\mu}{\sigma} > \frac{x-460}{40} ) = 0.10

        P(Z > \frac{x-460}{40} ) = 0.10

<em>So, the critical value of x in the z table which represents the top 10% of the area is given as 1.2816, that is;</em>

<em>                   </em>      \frac{x-460}{40} =1.2816

                         {x-460}{} =1.2816\times 40

<em>                           </em>x = 460 + 51.264 = <u>511.264 seconds</u>

Hence, the time that the boys need to beat in order to earn a certificate of recognition from the fitness association is 511.264 seconds.

8 0
3 years ago
Mira picked two numbers from a bowl. The difference of the two numbers was 4, and the sum of one-half of each number was 18. The
kobusy [5.1K]

Answer:

20 and 16

Step-by-step explanation:

Let us find x and y.

x – y = 4 _____(1)

x/2 + y/2= 18___(2)

Multiply (2) by 2 and add to (1)

  x - y = 4

+<u>(x + y = 36)</u>

 <u>2x   =   40</u>

=> x = 40 / 2 = 20

From (1):

20 - y = 4

=> y = 20 - 4 = 16

The two numbers are 20 and 16.

6 0
3 years ago
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