Point A' is the image of point A when point A is rotated about the origin B. What angle in the counterclockwise direction is
1 answer:
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Answer:
7.
8.
Step-by-step explanation:
We are given two function, f(x) and g(x).
We want to find their addition and their subtraction, and we do this combining like terms.
The functions are:
7. Find (f+9) (x)
So
8. Find (f - g) (x)
So
a. The velocity t =
b. v60 = 7164
<h3>How to solve for the velocity</h3>mdv/dt = ck - mg
dv/dt = ck/m - mg/m
= ck/m - g
dv =
Integrate the two sides of the equation to get
v
b. fuel accounts for 55% of the mass
So final mass after fuel is burned out is = 0.45
c=2500
g=9.8
t=60
v = -2500ln0.45 - 9.8 x 60
= 7752 - 588
= 7164
<h3>Complete question</h3>A rocket, fired from rest at time t = 0, has an initial mass of m0 (including its fuel). Assuming that the fuel is consumed at a constant rate k, the mass m of the rocket, while fuel is being burned, will be given by m0 - kt. It can be shown that if air resistance is neglected and the fuel gases are expelled at a constant speed c relative to the rocket, then the velocity of the rocket will satisfy the equation where g is the acceleration due to gravity.
dv dt m =ck - mg
(a) Find v(t) keeping in mind that the mass m is a function of t.
v(t) =
m/sec
(b) Suppose that the fuel accounts for 55% of the initial mass of the rocket and that all of the fuel is consumed at 60 s. Find the velocity of the rocket in meters per second at the instant the fuel is exhausted. [Note: Take g = 9.8 m/s² and c = 2500 m/s.]
v(60) =
m/sec [Round to nearest whole number]
Raed more on velocity here
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Answer:
Yes, but it is not linear. It is exponential :
Step-by-step explanation:
On the first day we have 5 bacteria.
On the second day we will have 5*2 = 10 bacteria.
On the third day we will have 10*2 = 5*2*2 = 5*2^2 = 20 bacteria.
On the fourth day we will have 20*2 = 5*2*2*2 = 5*2^3 = 40 bacteria.
We can see that
,
where x is a number of days and f(x) gives us the number of bacteria.