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EleoNora [17]
3 years ago
12

What number meets the following characteristics, is rational, less than 0, greater than negative 4, and is not an integer NEED A

NSWER FAST
Mathematics
2 answers:
EleoNora [17]3 years ago
6 0

Answer: - 3/4

Step-by-step explanation:

It fits

dem82 [27]3 years ago
5 0

So let's narrow it down.

Less than 0, greater than -4

That gives us three whole numbers, -3, -2, and -1.

So that does not really narrow it down, because all of those aren't integers and are rational.

Any other information?

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Solve this system of equations using the substitution method<br> y = 2x + 17<br> y = 6x - 3
guapka [62]

Step-by-step explanation:

well, as you can witness both of the equations are equal to y, so you're free to reckon that they are equal as well

6x - 3 = 2x + 17 =  =  =  > \\  4x = 20 =  =  =  > x = 5 \: and \:  \\ y = 6(5)  - 3=  =  =  > y = 27

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2 years ago
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Answer:

14

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Answer both questions please!!! I need help....
Temka [501]

Answer

The first one is equal and the second one is the first choice.

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3 years ago
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7n+12=1/2(14n+24)<br><br><br> NEED ANSWER ASAP
Angelina_Jolie [31]

Answer:

n = all real numbers

Step-by-step explanation:

7n+12=1/2(14n+24)

multiply each side by 2

2(7n+12)=2*1/2(14n+24)

distribute

14n+24 = 14n + 24

subtract 14n from each side

14n-14n+24 = 14n-14n + 24

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3 0
3 years ago
How would you solve this by elimination?
jekas [21]
To solve this equation by elimination, what you would do is multiply one of the equations by -1, or distribute -1 to each term in the equation, any of the 2 equations. Then align the equations and add them together.

-(X + 3y = 3)
-X - 3y = -3

-X - 3y = -3
X + 6y = 3
__________
3y = 0
y = 0/3 = 0.

Now we can solve for x, by simply plugging the value of y into any of the 2 equations.

X + 6y = 3
X + 6(0) = 3
X + 0 = 3
X = 3.

The solution to your system of equations would be (3,0).

Check this by plugging in the point to the other equation and see if it is true.

X + 3y = 3
(3) + 3(0) = 3
3 + 0 = 3
3 = 3.

Thus it is the solution.
5 0
3 years ago
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