Answer:
Explanation:
1. Write a program that declares an array named alpha with 50 components of the type double. Initialize the array so that the first 25 components are equal to the square of the counter (or index) variable and the last 25 components are equal to three times the index variable.
double alpha[50];
for (int i=0;i<25;i++)
{
alpha[i]=i*i;
alpha[i+25]=(i+25)*3;
}
2. Output the array so that exactly ten elements per line are printed.
for (int i=0;i<50;i++)
{
cout<<i+1<<". "<<alpha[i]<<" ";
if (((i+1)%10)==0)
{
cout<<endl;
}
}
3. Run your program again, but this time change the code so that the array is filled with random numbers between 1 and 100.
double alpha[50];
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
}
for (int i=0;i<50;i++)
{
cout<<i+1<<". "<<alpha[i]<<" ";
if (((i+1)%10)==0)
{
cout<<endl;
}
}
4. Write the code that computes and prints the average of elements of the array.
double alpha[50],temp=0;
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
temp+=alpha[i];
}
cout<<"Average :"<<(temp/50);
5. Write the code that that prints out how many of the elements are EXACTLY equal to 100.
double alpha[50],temp=0;
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
if(alpha[i]==100)
{
temp++;
}
}
cout<<"Elements Exacctly 100 :"<<temp;
Please note: If you put each of above code to the place below comment it will run perfectly after compiling
#include <iostream>
using namespace std;
int main()
{
// If you put each of above code here it will run perfectly after compiling
return 0;
}
Answer:
The answers are explained below
Explanation:
1) Identify the potential classes in this problem domain be list all the nouns
class Customer
class Acco unt
2) Refine the list to include only the necessary class names for this problem
the class customer is not necessary to solve the problem itself, therefore the only class could be the account class
3) Identify the responsibilities of the class or classes.
The responsibilities of the class account will be
* determination of the type of account--> Acc ount . type(char)
* deposit money into the account --> Acc ount . de posit(float)
* withdraw money into the account --> Acc ount . with draw(float)
* show balance of the account --> Acc ount . bal ance()
* generate interest --> Acc ount . int erest()
Please join the words together. I used spaces due to regulations
Answer:
See attachment fir procedures to get answers.
Explanation:
Given that;
In the Database sheet, enter conditions in the criteria range for unoccupied two- and three-bedroom apartments that need to be remodeled. Enter criteria as text only, without use of quotation marks. Be sure to enter the criteria separately in rows 3 and 4.
See attachment
Answer:
B. n-1
Explanation:
If there are n vertices then that vertex can be origin of at most n-1 edges.Suppose that you have a graph with 8 vertices you can select a vertex from these 8 vertices now you have 7 other vertices.So the vertex you selected can have at most 7 edges or it can be origin of at most 7 edges.So we conclude that the answer is n-1.
