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3 years ago

Methods that require you to use an object to call them are called ____ methods.1. accessor2. instance3. internal4. static

Computers and Technology

1 answer:

spin [16.1K]3 years ago

3 0

Answer:

Option 2 i.e., instance methods is the correct answer to the following question.

Explanation:

Because the instance method or function is the function that needed the class object to be called.

<u>For Example:</u>

//header file

#include <iostream>

using namespace std;

//define class

class Test

{

public:

//instance method

void getins()

{

cout<<"I AM Instance method";

}

};

int main()

{

//creating object

Test obj;

//calling of instance method through class object

obj.getins();

}

<u>Output</u>:

I AM Instance method

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Answer:

Here is the program:

#include <iostream> //to use input output functions

#include <string> // to use functions to manipulate strings

using namespace std; //to identify objects cin cout

void function(string prefix, unsigned int levels){ // function that takes two parameters, a string, using the string class and levels an unsigned integer

if (levels == 0) { //if number of levels is equal to 0

cout << prefix << endl; //displays the value of prefix

return; }

for (int i = 1; i <=9 ; i++){ //iterates 1 through 9 times

string sections = (levels == 1 ? "" : "."); //if the number of levels is equal to 1 then empty space in sections variable otherwise stores a dot

string output = prefix + std::to_string(i) + sections; // displays the string prefix followed by the section numbers. Here to_string is used to convert integer to string

function(output, levels - 1); } } //calls function by passing the resultant string and levels-1 recursively to print the string prefix followed by section numbers

int main() { // start of main function

int level = 2; //determines the number of levels

function("BOX", level); } //calls function by passing the string prefix and level value

Explanation:

The program has a function named function() that takes two parameters, prefix (a string, using the string class from ) and levels (an unsigned integer). The function prints the string prefix followed by "section numbers" of the form 1.1., 1.2., 1.3., and so on. The levels argument determines how many levels the section numbers have. If the value of levels is 0 means there is 0 level then the value of prefix is printed. The for loop iterates '1' through '9' times for number of digits in each level. If the number of levels is 1 then space is printed otherwise a dot is printed. The function() calls itself recursively to print the prefix string followed by section numbers.

Let us suppose that prefix = "BOX" and level = 1

If level = 1 then the loop for (int i = 1; i <=9 ; i++) works as follows:

At first iteration:

i = 1

i <=9 is true because value of i is 1

string sections = (levels == 1 ? "" : "."); this statement checks if the levels is equal to 1. It is true so empty space is stored in sections variable so,

sections = ""

Next, string output = prefix + std::to_string(i) + sections; statement has prefix i.e BOX plus value of i which is 1 and this int value is converted to string by to_string() method plus sections has an empty space. So this statement becomes

string output = BOX + 1

So this concatenates BOX with 1 hence output becomes:

output = BOX1

At second iteration:

i = 2

i <=9 is true because value of i is 2

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix + std::to_string(i) + sections; statement becomes

string output = BOX + 2

So this concatenates BOX with 1 hence output becomes:

output = BOX2

At third iteration:

i = 3

i <=9 is true because value of i is 3

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix + std::to_string(i) + sections; statement becomes

string output = BOX + 3

So this concatenates BOX with 1 hence output becomes:

output = BOX3

Now at each iteration the prefix string BOX is concatenated and printed along with the value of i. So at last iteration:

At last iteration:

i = 9

i ==9 is true because value of i is 9

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix + std::to_string(i) + sections; statement becomes

string output = BOX + 9

So this concatenates BOX with 1 hence output becomes:

output = BOX9

After this the loop breaks at i = 10 because the condition i<=9 becomes false. So the output of the entire program is:

BOX1 BOX2 BOX3 BOX4 BOX5 BOX6 BOX7 BOX8 BOX9

The program along with the output is attached.

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Answer:

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Complete Question:

Assume that an array of Integers named a that contains exactly five elements has been declared and initialized. In addition, an int variable j has also been declared and initialized to a value somewhere between 0 and 3.

Write a single statement that assigns a new value to the element of the array indexed by j. This new value should be equal to twice the value stored in the next element of the array (i.e. the element after the element indexed by j ). Do not modify any other elements of the array!

Answer:

a[j] = 2 * a[j+1];

Explanation:

Since the array is named a and its indexes are referenced by the variable j

it means the elements of the array will be a[j] for (j=0; j=1;j=2).

The first element in the array (j=0) will be a[0], second element will be a[1] and so on.

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3 years ago