Marcus' employee benefits include family health care coverage. He contributes 25% of the cost. Marcus gets paid weekly and $102
1 answer:
You might be interested in
Hi there! The answer is B.
First we work out the parenthesis, which is easy because we can just remove them.
Now rearrange our expression (in order to collect terms later).
Next up is collecting the terms.
The answer is B.
~ Hope this helps you!
First we work out the parenthesis, which is easy because we can just remove them.
Now rearrange our expression (in order to collect terms later).
Next up is collecting the terms.
The answer is B.
~ Hope this helps you!
9514 1404 393
Explanation:
We refer to the equations as [1] and [2]. We refer to the items as (1) – (4).
__
1. The terms to be eliminated have matching coefficients in (1) and (2). They can be eliminated by subtracting one equation from the other.
In (3) and (4), putting the equations in standard form* results in terms with opposite coefficients. Those terms can be eliminated by adding the equations.
__
2. Terms to be eliminated will have matching or opposite coefficients.
__
3. In (1) and (2), the variable x can be eliminated by subtracting one equation from the other. In the attachment, we have indicated the subtraction that will result in the remaining variable having a positive coefficient.
__
4. In (3) and (4), the coefficients of the variables are not equal or opposite in the two equations, so no variable can be eliminated directly.
__
5. As suggested by the answer to Q4, an equivalent equation must be found that has an equal or opposite variable coefficient with respect to the other equation. The new equations are ...
(3) [2] ⇒ x -y = 2
(4) [1] ⇒ 2x +2y = 3
_____
Here are the solutions:
(1) [1] -[2] ⇒ (x +y) -(x -y) = (-1) -(3)
2y = -4 ⇒ y = -2
x = y +3 = 1 . . . . from [2]
(x, y) = (1, -2)
__
(2) [2] -[1] ⇒ (x +2y) -(x +y) = (8) -(5)
y = 3
x = 5 -y = 2 . . . . from [1]
(x, y) = (2, 3)
__
(3) [1] +[2]/2 ⇒ (x +y) +(x -y) = (1) +(2)
2x = 3 ⇒ x = 3/2
y = 1 -x = -1/2 . . . . from [1]
(x, y) = (3/2, -1/2)
__
(4) [2] +[1]/2 ⇒ (5x -2y) +(2x +2y) = (4) +(3)
7x = 7 ⇒ x = 1
y = (3 -2x)/2 = 1/2
(x, y) = (1, 1/2)
_____
* Equations in standard form have mutually prime coefficients. In (3) a factor of 2 can be removed from equation [2]. In (4), a factor of 2 can be removed from equation [1].
