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GaryK [48]
3 years ago
13

Is c^2 - 6c +9 a perfect square?

Mathematics
2 answers:
katrin [286]3 years ago
6 0

Answer:(c-3)(c-3) yes

Step-by-step explanation:

C²-6c-9

(c²-3c-)(3c+9)

c(c-3)-3(c-3)

(c-3)(c-3)

Anni [7]3 years ago
3 0

Step-by-step explanation:

{c}^{2}  - 6c + 9 \\  =  {c}^{2}  - 2 \times 3 \times c +  {3}^{2}  \\  = (c - 3)^{2}  \\

Therefore, c^2 - 6c +9 is a perfect square.

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Answer:

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Step-by-step explanation:

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3 years ago
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20 people reported enjoying dancing and 11 of them were under 40. What percentage of people who enjoy dancing are under 40 years
Nikolay [14]

Step-by-step explanation:

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3 years ago
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(2/3 - 3/4 × 1/8) ÷ (2/3 - 3/4 + 5/8)
kati45 [8]
<h3>Given:</h3>

( \frac{2}{3}  -  \frac{3}{4}  \times  \frac{1}{8} ) \div ( \frac{2}{3}  -  \frac{3}{4}  +  \frac{5}{8} )

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First, solve the brackets.

First bracket:

( \frac{2}{3}  -  \frac{3}{4}  \times  \frac{1}{8} )

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Second bracket:

( \frac{2}{3}   - \frac{3}{4}  +  \frac{5}{8} )

=  \frac{13}{24}

Then divide.

\frac{55}{96}  \div  \frac{13}{24}

=  \frac{55}{52}  \: or \:  1\frac{3}{52}

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