Is c^2 - 6c +9 a perfect square?

Mathematics

2 answers:

katrin [286]2 years ago

6 0

Answer:(c-3)(c-3) yes

Step-by-step explanation:

C²-6c-9

(c²-3c-)(3c+9)

c(c-3)-3(c-3)

(c-3)(c-3)

Anni [7]2 years ago

3 0

Step-by-step explanation:

${c}^{2} - 6c + 9 \\ = {c}^{2} - 2 \times 3 \times c + {3}^{2} \\ = (c - 3)^{2} \\$

Therefore, $c^2 - 6c +9$ is a perfect square.

You might be interested in

Which solid has zero faces, zero bases, zero vertices, and zero edges?

svlad2 [7]

The only solid <span>zero faces, zero bases, zero vertices, and zero edges is a sphere. The reason why is because it's just round, and it doesn't have anything, just a sphere.

Have a nice day! :)</span>

3 0

3 years ago

Read 2 more answers

Please help i am being timed!!!!!!

Ivahew [28]

Answer:

fnjfc ij vcd d GB hhv

Step-by-step explanation:

tb f thg. kufc if fyi uuj

3 0

2 years ago

Assume that women have heights that are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches.

Maurinko [17]

Answer:

Q3 = 65.7825.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 63.6, \sigma = 2.5$