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3 years ago

Is c^2 - 6c +9 a perfect square?

Mathematics

2 answers:

katrin [286]3 years ago

6 0

Answer:(c-3)(c-3) yes

Step-by-step explanation:

C²-6c-9

(c²-3c-)(3c+9)

c(c-3)-3(c-3)

(c-3)(c-3)

Anni [7]3 years ago

3 0

Step-by-step explanation:

${c}^{2} - 6c + 9 \\ = {c}^{2} - 2 \times 3 \times c + {3}^{2} \\ = (c - 3)^{2} \\$

Therefore, $c^2 - 6c +9$ is a perfect square.

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65 people and 40% got refreshments how many boight refreshments

liberstina [14]

Multiply 65 by .4 and subtract that number from 65<span />

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3 years ago

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Simplify each term. please help!! 30 points + brainliest :)

Sunny_sXe [5.5K]

Answer:

1. 27y^3

2. 32c^5

3. 16m^4

4. 64g^3

5. 49j^2

6. -3125z^5

Step-by-step explanation:

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3 years ago

What is the solution to the system of equations below?

kifflom [539]

Answer:

(-5,-14)

Step-by-step explanation:

To find the solution of the system of two equations

$\left\{\begin{array}{l}y=4x+6\\y=2x-4\end{array}\right.$

equate right sides of these two equations:

$4x+6=2x-4$

Rewrite terms with x into the left side and without x into the right side:

$4x-2x=-4-6\\ \\2x=-10\ [\text{divide by 2}]\\ \\x=-5$

Substitute x=-5 into the first equation:

$y=4\cdot (-5)+6=-20+6=-14$

The solution is (-5,-14)

4 0

3 years ago

"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen

Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± $Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ ]

Where

p' is the sample proportion/point estimator of the population proportion

$Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$ is the margin of error (d) of the confidence interval.

$Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648$

$d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }$

$d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }$

$(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}$

$n*(d*Z_{1-\alpha /2})^2= p'(1-p')$

$n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}$

$n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}$

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0

3 years ago

Subtract. Write the answer in standard form. (12+4i)−(3−7i)

LiRa [457]

Answer:

9+11i

Step-by-step explanation:

12-3=9

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8 0

3 years ago

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