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3 years ago

Felix wants to buy some lemonade for the dinner party.

Mathematics

1 answer:

Xelga [282]3 years ago

6 0

Answer:

Yes. Felix is correct.

Step-by-step explanation:

Find out how much ml does a can of lemonade have, I would assume its 330ml since I searched up the ml of a lemonade can.

Find out how much cans of lemonade there are in 2 packs of 8.

2 packs = 8 x 2 = 16 cans of lemonade

Now find out how much ml 16 lemonade cans equal to.

1 can of lemonade = 330ml

16 cans of lemonade = 330 x 16 = 5280ml

Now let's find 5 bottles of 1 litre.

1 litre x 5 = 5 litres.

5280 = 5 litres and 280ml

So Felix is correct about 2 packs of 8 cans is more than 5 bottles of 1 litre.

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Lera25 [3.4K]

Answer:

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Step-by-step explanation:

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3 years ago

Salinda borrowed $4,200 to buy some furniture Her monthly payments over four years with an interest rate of 24 percent are $136.

Serga [27]

Answer:

1008

Step-by-step explanation:

All you have to do is find what 24 percent of 4200 is.

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2 years ago

In the figure below, FH= 14 and GH=6. Find FG.

Katyanochek1 [597]

Answer:

Let's see what to do buddy....

Step-by-step explanation:

_________________________________

FG = FH + HG ----¢ FG = 14 + 6 = 20

FG = 20

And we're done.

Thanks for watching buddy good luck.

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3 years ago

At 6 a.m. the temperature was 18oF. By noon it had risen to 36oF. A student claimed that it was then "twice as warm" as it was a

mart [117]

Yes, 18 x 2 + 36, therefore the student was correct

4 0

3 years ago

Read 2 more answers

certain computer virus can damage any file with probability 35%, independently of other files. Suppose this virus enters a folde

Ksivusya [100]

Answer:

0.623 is the probability that between 800 and 850 files get damaged.

Step-by-step explanation:

We are given the following information:

We treat virus can damage computer as a success.

P( virus can damage computer) = 35% = 0.35

The conditions for normal distribution are satisfied.

By normal approximation:

$\mu = np = 2400(0.35) = 840\\\sigma = \sqrt{np(1-p)} = \sqrt{2400(0.35)(1-0.35)} = $$23.36$

We have to evaluate probability that between 800 and 850 files get damaged.

$P(800 \leq x \leq 850) = P(\displaystyle\frac{800 - 840}{23.36} \leq z \leq \displaystyle\frac{850-840}{23.36}) = P(-1.712 \leq z \leq 0)\\\\= P(z \leq 0.428) - P(z < -1.712)\\= 0.666 - 0.043 = 0.623 = 62.3\%$

$P(800 \leq x \leq 850) = 62.3\%$

0.623 is the probability that between 800 and 850 files get damaged.

8 0

3 years ago