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3 years ago

Camilla has three times as many points as Lynn. Lynn has five

Mathematics

1 answer:

REY [17]3 years ago

5 0

Step-by-step explanation:

l x 3 = c

k + 5 = l

(c + l + k) x 2 = 25

c = 33

l = 11

k = 6

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Simplify.<br> Remove all perfect squares from inside the square root.<br> √/3065 =

REY [17]

There are none. The factors are 1, 5, 613, and of course 3065 and none are perfect squares.

4 0

2 years ago

What is the arc length when Θ = 4 pi over 7 and the radius is 5 cm?

xxTIMURxx [149]

$\bf \textit{arc's length}\\\\
s=r\theta \qquad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad radians\\
------\\
r=5\\
\theta =\frac{4\pi }{7}
\end{cases}\implies s=5\cdot \cfrac{4\pi }{7}$

8 0

3 years ago

Alfonso runs 10 km at an average speed of x km/h.

puteri [66]

Step-by-step explanation:

Note that t = d/r where t is time, d is distance, and r is rate/speed.

We can come up with two equations with the information given and the equation:

t_1 hr = (10 km)/(x km/hr)

t_2 hr = (12 km)/(x - 1 km/hr)

<em>where t_1 is the time taken to run the 10km the first day and t_2 is the time taken to run the 12km the second day.</em>

We know that 30 minutes is 1/2 of an hour and that t_1 is 30 minutes less than t_2 (as stated in the question). Therefore, we can write:

t_1 = t_2 - 1/2

Substituting the values we derived:

(10 km)/(x km/hr) = (12 km)/(x - 1 km/hr) -1/2

Then we can evaluate by multiplying by 2x(x-1) on both sides:

20(x-1) = 24x - (x)(x-1)

20x - 20 = 24x - x^2 + x

x^2 -5x -20 = 0

And we are done.

I hope this helps! :)

6 0

2 years ago

If you get this you are a critical thinker.

Alchen [17]

Answer:

Step-by-step explanation:

If you killed 30 and there were 34 people there not including me then there would be 5 left.

4 0

3 years ago

Read 2 more answers

An object is launched from ground level with an initial velocity of 120 meters per second. For how long is the object at or abov

babunello [35]

Answer:

D) 14 seconds

Step-by-step explanation:

First we will plug 500 in for y:

500 = -4.9t² + 120t

We want to set this equal to 0 in order to solve it; to do this, subtract 500 from each side:

500-500 = -4.9t² + 120t - 500

0 = -4.9t²+120t-500

Our values for a, b and c are:

a = -4.9; b = 120; c = -500

We will use the quadratic formula to solve this. This will give us the two times that the object is at exactly 500 meters. The difference between these two times will tell us when the object is at or above 500 meters.

The quadratic formula is:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Using our values for a, b and c,

$x=\frac{-120\pm \sqrt{120^2-4(-4.9)(-500)}}{2(-4.9)}\\\\=\frac{-120\pm \sqrt{14400-9800}}{-9.8}\\\\=\frac{-120\pm \sqrt{4600}}{-9.8}\\\\=\frac{-120\pm 67.8233}{-9.8}\\\\=\frac{-120+67.8233}{-9.8}\text{ or }\frac{-120-67.8233}{-9.8}\\\\=\frac{-57.1767}{-9.8}\text{ or }\frac{-187.8233}{-9.8}\\\\=5.3242\text{ or }19.1656$

The two times the object is at exactly 500 meters above the ground are at 5 seconds and 19 seconds. This means the amount of time it is at or above 500 meters is

19-5 = 14 seconds.

6 0

3 years ago