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erik [133]
3 years ago
7

How do I graph -6x > 30 or x+5 > or =to 2 on a number line?

Mathematics
1 answer:
Basile [38]3 years ago
7 0

Step-by-step explanation:

-6x > 30

x< -5 (open circle from -5 to the left)

x + 5 > or = 2

x > or = -3 (closed circle from -3 to the right)

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Suppose in the University of Manitoba, 40% of the students live in apartments. If 600 students are randomly selected, then the a
just olya [345]

Answer:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and X \sim Bin(n=600, p =0.4)

And we want this probability:

P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.&#10;[tex]np=600*0.4=240\geq 10

n(1-p)=600*(1-0.4)=360 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=600*0.4=240

\sigma=\sqrt{np(1-p)}=\sqrt{600*0.4(1-0.4)}=12

And then X \sim N (\mu = 240, \sigma= 12)

And we are interested on the following probability:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

6 0
3 years ago
All real cube roots of 27
Delvig [45]
The answer is 3, since 3*3*3 equals 27
6 0
3 years ago
(y+3) solve by using the distributive property ​
MA_775_DIABLO [31]

Answer:

y-3

Step-by-step explanation:

4 0
3 years ago
What are the x-intercepts of the equation?<br> <img src="https://tex.z-dn.net/?f=r%28x%29%20%3D%20x-1%2Fx%2B4" id="TexFormula1"
cestrela7 [59]

Answer:

<u>The only x-intercept is x = 1</u>

Step-by-step explanation:

The equation is:

r(x)=\frac{x-1}{x+4}

We can substitute y for r(x), to write in the notation:

r(x)=\frac{x-1}{x+4}\\y=\frac{x-1}{x+4}

To get y-intercept, we put x = 0

and

To get x-intercept, we put y =0

We want to find x-intercepts here, so we substitute 0 into y and solve for x. Shown below:

y=\frac{x-1}{x+4}\\0=\frac{x-1}{x+4}\\0(x+4)=x-1\\0=x-1\\x=1

<u>The only x-intercept is x = 1</u>

3 0
3 years ago
Please help please and please actually answer please
SOVA2 [1]

Answer:

#3

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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