We have been given that the ages of students in a school are normally distributed with a mean of 15 years and a standard deviation of 2 years.
We are asked to find the percentage of students that are between 14 and 18 years old.
First of all, we will find z-score corresponding to 14 and 18 using z-score formula.




Similarly, we will find the z-score corresponding to 18.



Now we will find the probability of getting a z-score between
and
that is
.

Using normal distribution table, we will get:


Let us convert
into percentage.

Therefore, approximately
of the students are between 14 and 18 years old.
Fy = 2 because we derivate in raport witw y and x is like a constant;
fyx = 0 because we deivare in raport with x.
When we say "5 is the third part of 15," we do not imply a sequence: the first part, the second part, the third, and so on. When we speak of the third part, that is a different meaning for the word "third." It means each one of three equal parts that together make up the whole
Answer:
D is the right answer
5(0) + 3(5) =15
5(3) + 3(0) =15
Step-by-step explanation: