1 is the answer for this question.
Answer:
4, -19
Step-by-step explanation:
Answer:
x(t) = 5000*( 1 - e^-kt)
Step-by-step explanation:
Given:
- Total number of students n = 5000
Find:
Differential equation governing the number of students x(t) who have contracted the flu.
Solution:
- Number of non-affected students = (5000 - x)
Hence,
- Rate at which students are infected:
dx / dt = k*(5000 - x )
- separate variables:
dx / (5000 - x ) = k*dt
- Integrate both sides:
- Ln(5000 - x) = kt + C
- Evaluate C for x = 0 @ t = 0
- Ln(5000 - 0) = k*0 + C
C = - Ln(5000)
- The solution to ODE is:
Ln(5000 - x) = -k*t + Ln(5000)
5000 - x = 5000*e^-kt
x(t) = 5000*( 1 - e^-kt)
Answer:
209,000
Step-by-step explanation:
(500+200=700)
(700*300=210000)
210000-1000=209,000
2(x+4x)-4=4(x-3)+2(x+10)
2x+8x-4=4x-9+2x+20
10x-4=6x+11
10x=6x+15
4x=15
x=3.75
