Answer:
(things,can't think of more
.......)
- paper
- charcoal
- doors
- chairs
- jewelry
- wood frames
- broom handles
- furniture made with wood
Explanation:
bdhabsusvsjsvdhewjsbdueyssbwksv
Answer:
Both Technicians are correct.
Explanation:
Remember that Ohm's Law its a relationship between Voltage (E), Current (I) and Resistance (R) in an electrical circuit. This relationship is defined by the following equation:

Each one of the letters could be called a variable. Now, also remember that the number of equations you have is equal to the number of variables unknown you could have.
In Ohm's Law you have 3 variables (E,I,R) and 1 equation. It means that you need to know 2 variables (Whatever 2 variables) to know the third.
Technician A says, in other words, that could calculate the Circuit current flow (I) knowing total circuit resistance (R) and total voltage (E). Note that Technician A knows 2 to 3 variables, then it's possible to use Ohm's Law with the following equation:

Technician B says, in other words, that could determine the unknown resistance (R) knowing total current (I) and source voltage (E). Once again, note that Technician B knows 2 to 3 variables, then it's possible to use Ohm's Law with the following equation:

It is concluded that both technicians are right.
Answer:
a.material control failure
Explanation:
A material control failure is a material deficiency, or combination of significant deficiencies, that results in more than a remote likelihood that a material mis-statement in the annual or interim financial statements will not be prevented or detected.
Answer:
sentence = "hello wow a stores good"
same_letter_count = 0
sentence_list = sentence.split()
for s in sentence_list:
if s[0] == s[-1]:
same_letter_count += 1
print(same_letter_count)
Explanation:
*The code is in Python.
Initialize the sentence with a string
Initialize the same_letter_count as 0
Split the sentence using split method and set it to the sentence_list
Create a for loop that iterates through the sentence_list. If the first and last of the letters of a string are same, increment the same_letter_count by 1
When the loop is done, print the same_letter_count