False, (i'm not sure but I think that thats it)
The answer is a Scroll bar, the description fits perfectly because you need to move it to see more of the content you are viewing, and it wont be completely. when the item does appear completely on screen then the bar is relatively large and there is no need for scrolling, however the opposite occurs during when you cannot see all of it.
The correct answer is A it transfers control to the next loop in the program.
The most valid answer is that the break statement Exits the loop and continues executing the program, but assuming that there are other loops, the control of the program will go to them since the first loop is broken out of.
<span>#include <iostream>
using namespace std;
bool bears(int n);
int main(){
int number;
do{
cout<<"enter the amount of bears (press 0 to stop the program): ";
cin>>number;
if (bears(number)){
cout<<"you have reached the goal!"<<endl;
}
else{
cout<<"sorry, you have not reached the goal."<<endl;
}
}while(number != 0);
}
bool bears(int n){
if (n < 42){
return false;
}
else if (n == 42){
return true;
}
else{
if (n % 5 == 0){
return bears(n - 42);
}
else if(n % 2 == 0){
return bears(n / 2);
}
else if(n % 4 == 0|| n % 3 == 0)
{
int one;
int two;
one=n%10;
two=(n%100)/10;
return bears(n - one * two);
}
}
<span>}</span></span>
I think it’s number one...
