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3 years ago

Need CORRECT answer ASSP

Mathematics

1 answer:

Misha Larkins [42]3 years ago

5 0

Answer:

1. (4,5)

The average rate of change of f(x) remain constant (4). Over the interval (4,5), g(x)=5,2 exceeding the change of f(x).

2. None!! REMAIN CONSTANT AND INCREASE.

The rate of change of f(x) remain constant (4) and g(x) increases.

3. g(x) exceeds the value of f(x)

F(X)=31 < G(X)=35,7

4. EVENTUALLY.

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What are the slope and the y-intercept of the linear function that is represented by the table?

mafiozo [28]

Answer:

slope is -2 and the y-intercept is 12

Step-by-step explanation:

a key thing to remember: x is always equal to 0 when finding the y-intercept.

so if you look at the table for where 0 is, you get the point (0,12) meaning the y-intercept is 12.

to find the slope use the equation: slope= change in y/change in x

you can use any two points to find this.

lets take the points of the x-intercept (6,0) and the y-intercept (0,12)

12-0/0-6

12/-6

-2 = slope

8 0

3 years ago

Please help hahahahaaahahaahahaaha

Blababa [14]

Answer:

The answer is 22.

Step-by-step explanation:

Just well use a calculator. If you don't have that then use PEMDAS. Hope it helps.

5 0

2 years ago

Read 2 more answers

A triangle whose angles have measures x x+5 and x+10

nirvana33 [79]

the correct question is
A triangle whose angles have measures x x+5 and x+10.How do you find the measure of each angle?

we know that
The Sum of internal angles of any triangle = 180∘
so
[x+(x+5)+(x+10)]=180---------------> 3x+15=180----------> 3x=165-------> x=55°

the answer is
the measure of each angle is
x=55°
x+5=60°
x+10=65°

4 0

3 years ago

Calculate the area of the triangle with the following vertices (3, -7), (6, 4), (-2, -3)

Monica [59]

Answer:

$\boxed{\mathsf{A} \triangle = \red{\dfrac{67}{2}u.a}}$

Step-by-step explanation:

Let's follow up with the solution. Considering a triangle with the vertices $\mathsf{A(x_A, y_A)}$ , $\mathsf{B(x_B, y_B)}$ and $\mathsf{C(x_C, y_C)}$ , have a look at the representation in the cartesian plan.

From this representation we can say that the area (A) of a triangle through the knowledge of analytical geometry is given by the determinant of the vertices divided by two, mathematically,

$\mathsf{A} \triangle = \dfrac{\left| \begin{array}{ccc} \mathsf{x_A} & \mathsf{y_A }& 1 \\ \mathsf{x_B} & \mathsf{ y_B} & 1 \\ \mathsf{ x_C} & \mathsf{ y_C} & 1 \end{array} \right|}{2}$

So, applying this knowledge we're going to have,

$\mathsf{A} \triangle = \dfrac{\left| \begin{array}{ccc} 3 & -7 & 1 \\ 6 & 4 & 1 \\ -2 & -3 & 1 \end{array} \right|}{2}$

$\mathsf{A} \triangle = \dfrac{1}{2}\left[ \left.\begin{array}{ccc} 3 & -7 & 1 \\ 6 & 4 & 1 \\ -2& -3 & 1 \end{array} \right| \begin{array}{cc} 3 & -7 \\ 6 & 4 \\ -2 & -3 \end{array} \right]$