Okay first you have to divide
2 goes into 3
3/2
2 fits into 3 once
1 and the left over is 1 so
1 1/2
400×10=4000
400×2=800
50×10=500
50×2=100
2×10=20
2×2=4
4000+800+500+100+20+4=5,424
Check answer by multiplying 452 and 12
452×12=5,424
94 - 30/6 * 1194-5 * 1194 - 5539
200/160=1.25
200+160=360/1.25/160=200.8
so your answer is 0.8
R(x) = 60x - 0.2x^2
The revenue is maximum when the derivative of R(x) = 0.
dR(x)/dx = 60 - 0.4x = 0
0.4x = 60
x = 60/0.4 = 150
Therefore, maximum revenue is 60(150) - 0.2(150)^2 = 9000 - 4500 = $4,500
Maximum revenue is $4,500 and the number of units is 150 units
