Answer:
x-6
Step-by-step explanation:
The mistake when expanding the bracket 3(x-6),3 was supposed to multiply 6 but instead it was added to 6 instead
the correct working
3(x-6)+(4x+12)-6x
3x-18+4x+12-6x
(3x+4x-6x)+(-18+12)
=x-6
Oh ok so square root of 2 is irrational since it goes on and on. square root of 18 is an irrational number too
You have to use the equation (72+y)=5(4+y) which Y =+13
So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
Learn more about Intermediate Value Theorem on:
brainly.com/question/11377865
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