Answer:
length is 78
Step-by-step explanation:
Perimeter of rectangle is P = 2 (l +w)
278 = 2(l + 61)
l = 78
he solution set is
{
x
∣
x
>
1
}
.
Explanation
For each of these inequalities, there will be a set of
x
-values that make them true. For example, it's pretty clear that large values of
x
(like 1,000) work for both, and negative values (like -1,000) will not work for either.
Since we're asked to solve a "this OR that" pair of inequalities, what we'd like to know are all the
x
-values that will work for at least one of them. To do this, we solve both inequalities for
x
, and then overlap the two solution set
It takes 15 minutes for Ms. Peter to drive from park to her home
Given :
from her home to the park at an average speed of 30 miles per hour and
returned home along the same route at an average speed of 40 miles per hour
it takes 20 minutes to travel
Convert 20 minutes in to hour (divide by 60)
20 minutes = 1/3 hour
We know that distance = speed x time
From home to park, distance =
So , distance between home and park is 10 miles
Now we calculate the time taken to return from park to home

Time taken is 1/4 hours. Convert it into minutes by multiplying by 60

So it takes 15 minutes for Ms. Peter to drive from park to her home
Learn more : brainly.com/question/18839247
Answer:
The value of currents are
,
and
.
Step-by-step explanation:
The Ohm's law states that

it is given that the V₁=3V and V₂=4V.
In a parallel circuit:
- Voltage is same in each component
- Sum of the currents equals to the total current that flows.
.... (1)
Equation for first loop is,

..... (2)
Equation for second loop is,

..... (3)
On solving (1), (2) and (3) we get



Therefore the value of currents are
,
and
.
Definition of eo-primes or relatively primes: Two numbers are said to be co-prime or relatively prime If their HCF IS 1 Hence to prove 847 and 2160 as co-prime numbers we will find their HCF and which should be 1
New steps to find HCF will be as under
2160 = 847 x 2+ 466
847 = 466 ×1 +381
466 = 381 x 1 + 85
381 =85 x 4+ 41
85 =41 x 2+3
41 =3 x 13+ 2
3 =2 x 1+1
2 =1 x 2+0
Therefore, the HCF=1 Hence, the numbers are co-primes (relatively prime).