Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
Answer:
Refer to the picture that given
Step-by-step explanation:
:))
Answer: 
Step-by-step explanation:
You need to set up two cases (Positive case and negative case) and solve for "x".
- POSITIVE CASE IF: 
- NEGATIVE CASE IF: 
Therefore, the solution is:
Answer:
24x^7 = 24x^7
Step-by-step explanation:
Left side of equation: 3 times 8 times X = 24x
Then you raise it to the 7th power
Right side of the equation: 6 times 4 times X = 24x
Since the exponent is the same, you keep it as the 7th power
(8 + [7+1] 2 ÷ 4 × 1) ÷ 2^4
Let's focus on what's in parentheses first.
8 + 8 × 2 ÷ 4 × 1
8 + 16 ÷ 4 × 1
8 + 4 × 1
8 + 4
12
Now, to what is outside the parentheses:
Because of the way it is written, you will do 12 ÷ 2 first.
12 ÷ 2^4
6^4
Answer: 1296
