All categories

3 years ago

Which transformation could be performed to show that ABC is Similar to A'B'C?

Mathematics

1 answer:

yulyashka [42]3 years ago

3 0

I think the one you have chosen in the picture is right

You might be interested in

50 POINTS!!!!!

likoan [24]

A. No
B. Yes
C. No
D. Yes

8 0

3 years ago

christa makes a bouquets of flowers so that the ratios are 5 roses to 4 daisies to 2 lilies christa makes a bouquet of 99 flower

pantera1 [17]

She uses 45 roses, 36 daisies, and 18 lilies. The reason is all of those fit the pattern used above and all of those are multiplied by the same number, making them equivalent

8 0

4 years ago

What is the volume of the rectangular prism if one side length is 1 2/5 and the other 3 1/3

Mamont248 [21]

Answer:

the length is one

Step-by-step explanation:

6 0

4 years ago

Find the missing length of the right triangle.

Oliga [24]

The answer is 15. Did both ways to see if I was correct. I did a2+b2=c2

8 0

3 years ago

The radius of a right circular cone is increasing at a rate of 1.9 in/s while its height is decreasing at a rate of 2.2 in/s. At

musickatia [10]

Answer:

Volume of the cone is increasing at the rate $9916\pi \frac{in^3}{s}$ .

Step-by-step explanation:

Given: The radius of a right circular cone is increasing at a rate of $1.9$ in/s while its height is decreasing at a rate of $2.2$ in/s.

To find: The rate at which volume of the cone changing when the radius is $134$ in. and the height is $136$ in.

Solution:

We have,

$\frac{dr}{dt} =1.9 \:\text{in/s}$ , $\frac{dh}{dt}=-2.2\:\text{in/s}$ , $r=134 \:\text{in}$ , $h=136\:\text{in}$

Now, let $V$ be the volume of the cone.

So, $V=\frac{1}{3}\pi r^{2}h$

Differentiate with respect to $t$ .

$\frac{dv}{dt} =\frac{1}{3}\pi \left [ r^2\frac{dh}{dt}+h\left ( 2r \right )\frac{dr}{dt} \right ]$

Now, on substituting the values, we get

$\frac{dv}{dt} =\frac{1}{3}\pi\left [ \left ( 134 \right )^2\left ( -2.2 \right )+\left ( 136\right )\left ( 2 \right )\left ( 134 \right )\left ( 1.9 \right ) \right ]$

$\frac{dv}{dt} =\frac{1}{3}\pi\left [ -39503.2+69251.2 \right ]$

$\frac{dv}{dt} =\frac{1}{3}\pi\left [ 29748 \right ]$

$\frac{dv}{dt} =9916\pi \frac{in^3}{s}$

Hence, the volume of the cone is increasing at the rate $9916\pi \frac{in^3}{s}$ .

6 0

3 years ago