Answer: The starting time is 2:27 and finishing time is 7:09.
Step-by-step explanation: It is given that Ben started from 4th street and he finished at 98th street.
Also, at 3:00, he was on 15th street and at 4:30, he was on 45th street.
That is, time taken to cover (45-15), i.e., 30 streets is 90 minutes, so the time taken to cover 1 street is 3 minutes.
Therefore, Ben covers distance from one street to second in 3 minutes. Since he started from 4th street, and there are 11 streets to cover between 4 and 15, so Ben's starting time was (3:00 - 3×11 min) = 2:27.
And his finishing time was (4:30 + 3×53 min) = 7:09.
Again, the equation that tells us on what street 'N' he was after time 'T' of his starting can be written as
Thus, the starting and finishing time was 2:27 and 7:09 respectively.
Answer: c. z = 1.35; Reject the null hypothesis
Step-by-step explanation:
Let 
be the average life expectancy of its batteries.
As per given , we have
Null hypothesis : 
Alternative hypothesis : 
Since 
is right-tailed and population standard deviation is also known, so we perform right-tailed z-test.
Test statistic : 
where, n= sample size
= sample mean
= Population mean
=population standard deviation
For 
, we have
Critical one-tailed test value for 0.10 significance level :
Decision : Since critical z value (1.28) < test statistic (1.35), so we reject the null hypothesis .
[When critical value is less than the test statistic value , we reject the null hypothesis .]
Answer:
2:55 P.M.
Step-by-step explanation:
First, add the amount of time Jim played outside; 45+55=100
100 minutes is equal to 1 hour 40 minutes.
If he left the playground at 4:35 P.M., then you have to subtract in order to find out when he arrived there.
Subtract 1 hour 40 minutes from 4:35 P.M. to then get 2:55 P.M.
To confirm your answer, you can add back the 1 hour and 40 minutes to 2:55 P.M. and you'll get 4:35 P.M.; back with what you started with.
Hope this helped !!!
