The correct answer is A.
lets discard the other options:
For B:
B is always positive, but f(x) is not, so B graph is not the answers
For C:
C is always positive too, so it cannot be the desire graph.
For D:
D is always negative, but we know that x exponent 3 is positive for all positive numbers,
Answer:
∠RST = 40°
Explanation:
We are given that:
SQ bisects angle RST.
This means that:
∠QST = ∠QSR
2x = 3x - 10
10 = 3x - 2x
x = 10
Therefore:
∠QST = 2x = 2(10) = 20°
∠QSR = 3x - 10 = 3(10) - 10 = 30 - 10 = 20°
Note that both angles are equal.
Now, we can get ∠RST as follows:
∠RST = ∠QST + ∠QSR
∠RST = 20 + 20 = 40°
Hope this helps :)
Use Pythagorean theory
C^2 = a^+ b^2
In this case you have c and a
B^2= c^2-a^2
B^2 = 12^2-5^2
B^2= 144-25
B^2 = 119
Square root both sides
X= 10.90871
BC is congruent to DC or BA is congruent to DA, depending on what point marks the intersection point of the two lines.
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