Answer:
6sqrt(2)
Step-by-step explanation:
You need to use the Right Triangle Altitude Theorem.
There are two parts to this theorem.
Here is the part you need for this problem.
If the altitude is drawn to the hypotenuse of a right triangle, the length of each leg of the right triangle is the geometric mean of the segment of the hypotenuse adjacent to the leg and the entire hypotenuse.
In this case, you end up with this proportion:
Length of leg: z
Length of entire hypotenuse = 8 + 1 = 9
Length of segment of hypotenuse adjacent to leg of interest: 8
8/z = z/9
z^2 = 72
z = sqrt(72)
z = sqrt(36 * 2)
z = 6sqrt(2)
Answer:
21cm, 12cm
Step-by-step explanation:
width=x cm
length=2x-3 cm
area= 252cm²
l*b= 252 cm²
(2x-3)(x)=252
2x²-3x= 252
this is how I did it
we need to find the nearest square of the number (it should be lesser than the area)
that is 225, whose square root is 15.
since there is a coefficient to the x², the value of x would be calculate like this 15- (2+1)= 15-3 = 12
x= 12
we can verify it too,
2*(12)² - 3*12=252
288-36=252
252=252
therefore width is 12 cm and width is 2*12-3= 24-3= 21 cm
verify;
21*12= 252
252=252
hence the dimensions are 12 am (width) and 21 cm(length).
Answer:
Step-by-step explanation:
If you meant
![\sqrt[3]{n^{75}}\\ \\ n^{{75}^{\frac{1}{3}}\\ \\ n^{\frac{75}{3}}\\ \\ n^{25}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bn%5E%7B75%7D%7D%5C%5C%20%5C%5C%20n%5E%7B%7B75%7D%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5C%5C%20%5C%5C%20n%5E%7B%5Cfrac%7B75%7D%7B3%7D%7D%5C%5C%20%5C%5C%20n%5E%7B25%7D)
Answer:
odd
Step-by-step explanation:
2/3 is greater than 3/5 because if you cross multiply, you'll get 10 on left side and 9 on the right, which means 3/5 is less than 2/3.
