Find a counterexample for the statement. If p is prime, then p2 + 4 is prime.
1 answer:
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Given :
To Find :
the absolute minimum and absolute maximum values of f on the given interval
[-1,2] .
Solution :
Now , getting first order differential equation and equating its equal to zero.
So , x=0 is critical point .
Now , coefficient of is positive .
Therefore , it is increasing function after x=0 .
So , min value will be at , x=0.
And maximum value will be the maximum at the x=2 because it is increasing function .
Therefore , max and min value is 9 and -3 respectively .
Hence , this is the required solution .