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2 years ago

Use inductive reasoning to describe the pattern of each sequence. Then find the next two terms. 1, 2, 5, 6, 9,

Mathematics

2 answers:

sladkih [1.3K]2 years ago

6 0

Answer:

continued: 10, 13, 14, 17, 18, 21....and so on

Step-by-step explanation:

The pattern for the sequence is it's counting by 1's then 3's then 1's and 3's again. It starts 1, count by one, you get 2, then the sequence changes. 2, count by three's, you get 5. This is the sequence but shown 1, 2 3 4 5, 6 7 8 9.

juin [17]2 years ago

5 0

It looks like the first 1 is the first problem, problem #1. (because of the period)
If this is the case, then the second sequence is 1, 0, -1, ...
1-1=0
0-1=-1
-1-1=-2
-2-1=-3
-3-1=-4
The sequence would then be 1, 0, -1, -2, -3, -4, ...

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My friend sets out walking at a speed of $3$ miles per hour. I set out behind her $5$ minutes later at $4$ miles per hour. When

r-ruslan [8.4K]

Answer: The answer is 0.25 miles.

Step-by-step explanation: Given that my friend started walking at a speed of 3 miles per hour and I started 5 minutes after him at a speed of 4 miles per hour. We need to find the number of miles my friend travelled when I started walking.

Since I started 5 minutes after than my friend, so we are to find the distance travelled by my friend in 5 minutes.

In 1 hour, i.e., 60 minutes, distance travelled by my friend = 3 miles.

In 1 minute, distance travelled by my friend is

$\dfrac{3}{60}=\dfrac{1}{20}~\textup{miles}.$

Therefore, distance travelled by my friend in 5 minutes will be

$\dfrac{1}{20}\times 5=\dfrac{1}{4}=0.25~\textup{miles}.$

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2 years ago

Read 2 more answers

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Inga [223]

Answer:

$V=2143.57\ mm^3$

Step-by-step explanation:

Given that,

The radius of the sphere, r = 8 mm

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$V=\dfrac{4}{3}\pi r^3$

Put all the values,

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2 years ago

Show that if the first 10 positive integers 1,2,3,···,10 are placed around a circle, in any order,there exists three integers in

zysi [14]

Answer:

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

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MrRa [10]

12.5% is the percentage of numbers randomly generated by Taylor's computer that is less than 0.5.

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P(0≤X≤0.5)

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